howru
9th December 2005 - 03:41 AM
A 18 kg child descends a slide 2.50 m high and reaches the bottom with a speed of 1.86 m/s. How much thermal energy due to friction was generated in this process?
I already asked you this question but i want to know if i have the right answer?
.5mv^2+mgh=.5mv^2
i got 1.12 m/s without friction so if took the proportion of that of 1.86 , it would be 1.66 m/s.
then i used the kinetic energy, and got 24.8 Joules
Nessus
9th December 2005 - 03:55 AM
Potential energy difference: E = mgh = 18*9.8*2.5 = 441J
Kinetic energy at the end: E = 1/2*mv^2 = 31.1364 J
Loss in energy is then approx 410 J