haha i didnt mean like all the atomic mass, just a proportion ,
As for the small amount of mass which is manipulated into energy, which part of the atom does the mass loss come from ?
Does this mean that the potential, or "stored" energy of a system is somehow proportional to a certain aspect of its mass ? and could possibly draw an equation for it ?
I'm guessing questions like that provide pretty advanced answers if there is one.
But I'm finding it rather interesting to research

Oh and ive been to my university library and visited the physics section
"On Space and time", "Ideas about particle physics" and "Elegant universe" are what I took out.
You know I said before I thought all energy was stored as Gravitational potential energy but it was clearly shown it wasn't enough for the neutrons and protons are held together are held together by Strong Force, and other forces Weak force??
Atoms are held together by Van der Vaals forces.
QUOTE
In physical chemistry, the van der Waals force (or van der Waals interaction), named after Dutch scientist Johannes Diderik van der Waals, is the sum of the attractive or repulsive forces between molecules (or between parts of the same molecule) other than those due to covalent bonds or to the electrostatic interaction of ions with one another or with neutral molecules.[1] The term includes:
force between two permanent dipoles (Keesom force)
force between a permanent dipole and a corresponding induced dipole (Debye force)
force between two instantaneously induced dipoles (London dispersion force)
It is also sometimes used loosely as a synonym for the totality of intermolecular forces. Van der Waals forces are relatively weak compared to normal chemical bonds, but play a fundamental role in fields as diverse as supramolecular chemistry, structural biology, polymer science, nanotechnology, surface science, and condensed matter physics. Van der Waals forces define the chemical character of many organic compounds. They also define the solubility of organic substances in polar and non-polar media. In low molecular weight alcohols, the properties of the polar hydroxyl group dominate the weak intermolecular forces of van der Waals. In higher molecular weight alcohols, the properties of the nonpolar hydrocarbon chain(s) dominate and define the solubility. Van der Waals-London forces grow with the length of the nonpolar part of the substance.
So the Energy released was stored as Energy in the atoms when they were separate but release energy (light or heat) because the electrons share orbitals (covalent bonds) which is a lower energy set up. Electrons loose energy by giving off a photon. So that holds them together because to separate them you would have to apply the right sort of energy.
QUOTE (->
| QUOTE |
In physical chemistry, the van der Waals force (or van der Waals interaction), named after Dutch scientist Johannes Diderik van der Waals, is the sum of the attractive or repulsive forces between molecules (or between parts of the same molecule) other than those due to covalent bonds or to the electrostatic interaction of ions with one another or with neutral molecules.[1] The term includes:
force between two permanent dipoles (Keesom force) force between a permanent dipole and a corresponding induced dipole (Debye force) force between two instantaneously induced dipoles (London dispersion force)
It is also sometimes used loosely as a synonym for the totality of intermolecular forces. Van der Waals forces are relatively weak compared to normal chemical bonds, but play a fundamental role in fields as diverse as supramolecular chemistry, structural biology, polymer science, nanotechnology, surface science, and condensed matter physics. Van der Waals forces define the chemical character of many organic compounds. They also define the solubility of organic substances in polar and non-polar media. In low molecular weight alcohols, the properties of the polar hydroxyl group dominate the weak intermolecular forces of van der Waals. In higher molecular weight alcohols, the properties of the nonpolar hydrocarbon chain(s) dominate and define the solubility. Van der Waals-London forces grow with the length of the nonpolar part of the substance. |
So the Energy released was stored as Energy in the atoms when they were separate but release energy (light or heat) because the electrons share orbitals (covalent bonds) which is a lower energy set up. Electrons loose energy by giving off a photon. So that holds them together because to separate them you would have to apply the right sort of energy.
A covalent bond is a form of chemical bonding that is characterized by the sharing of pairs of electrons between atoms. The stable balance of attractive and repulsive forces between atoms when they share electrons is known as covalent bonding.[1]
There doesn't seem to be a force involved in covalent bonds.
7slaterj
18th November 2011 - 07:17 PM
That confused me , had to read it a few times ha, I'm still not sure what "VAN DER VAAL " forces are haha.
Right, so the energy released in a reaction is something to do with the bonds between atoms. ahh im now all confused ha, i feel like i need to take chemistry all over again

When the covalent bonds form, the Electrons loose energy. . When the electron releases this energy as photons, does it also reduce in mass then ?
Robittybob1
18th November 2011 - 07:35 PM
QUOTE (7slaterj+Nov 18 2011, 07:17 PM)
That confused me , had to read it a few times ha, I'm still not sure what "VAN DER VAAL " forces are haha.
Right, so the energy released in a reaction is something to do with the bonds between atoms. ahh im now all confused ha, i feel like i need to take chemistry all over again

When the covalent bonds form, the Electrons loose energy. . When the electron releases this energy as photons, does it also reduce in mass then ?
yes by the mass of a photon E= mC^2 = frequency* planck's constant is that right?
I know you will say a photon has no mass but the mass of the chemical has lost a little. (I think).
There is conservation of energy and momentum but not mass.
Most on here treat my science as being slightly suspect - got that!
7slaterj
18th November 2011 - 07:44 PM
I just found a website called alternative physics dot com , The chapter named "matter-energy conversion" is rather interesting.
Its a whole book actually. Some of it far beyond my knowledge but could be interesting for you guys.
7slaterj
18th November 2011 - 07:48 PM
Ha i'm still confused :s
So the "massless photon" is the cause of the electron to loose mass ? Are we sure its the electron that looses mass ?
Robittybob1
18th November 2011 - 07:57 PM
QUOTE (7slaterj+Nov 18 2011, 07:48 PM)
Ha i'm still confused :s
So the "massless photon" is the cause of the electron to loose mass ? Are we sure its the electron that looses mass ?
My middle name isn't Einstein. It looses Energy, so it looses momentum, it may or may not loose mass.
But the whole amount of material will have lost mass.
Where are the others???? help/
7slaterj
18th November 2011 - 10:43 PM
momentum is mv, and loosing energy just decreases its velocity I suppose lol. i know kinetic energy is 0.5 mv^2 but have no idea if that applies in this case.
Yeh ! the others should help lol !
MjolnirPants
19th November 2011 - 12:57 AM
QUOTE (Robittybob1+Nov 18 2011, 02:35 PM)
There is conservation of energy and momentum but not mass.
Mass and energy are interchangeable, so conservation of energy is all that matters.
QUOTE
So the "massless photon" is the cause of the electron to loose mass ? Are we sure its the electron that looses mass ?
In the case of matter-antimatter reactions, it's not
just photons which are produced.
http://en.wikipedia.org/wiki/Annihilation
Robittybob1
19th November 2011 - 02:20 AM
QUOTE (MjolnirPants+Nov 19 2011, 12:57 AM)
Mass and energy are interchangeable, so conservation of energy is all that matters.
In the case of matter-antimatter reactions, it's not
just photons which are produced.
http://en.wikipedia.org/wiki/Annihilation
He was trying to understand in the case of an exothermic reactions where does the energy come from. If there is a change in mass what actually changes in mass.
I was thinking in covalent bonds was a electron thing so the energy was from the electron energy, then is it the electron that changes in mass?
It is probably on the web but who looks it up?
We have a saying "if all else fails read the instructions". Time for assistance.
7slaterj
19th November 2011 - 11:53 AM
E=MC^2
E=hv for a photon
so E=MC^2=hv
therfore ;
M=hv/C^2 ???
Could you use that to calculate the mass lost when its emmited from the electron ?
Robittybob1
19th November 2011 - 03:50 PM
QUOTE (7slaterj+Nov 19 2011, 11:53 AM)
E=MC^2
E=hv for a photon
so E=MC^2=hv
therefore ;
M=hv/C^2 ???
Could you use that to calculate the mass lost when its emitted from the electron ?
That does look like an equation I have seen before so it might work.
Check it out with a known amount of fuel and see it if holds (experimentally hold true).
MjolnirPants
21st November 2011 - 05:20 PM
QUOTE (7slaterj+Nov 19 2011, 06:53 AM)
E=MC^2
E=hv for a photon
so E=MC^2=hv
therfore ;
M=hv/C^2 ???
Could you use that to calculate the mass lost when its emmited from the electron ?
Let's break it down, we'll start with E=mc^2:
E is the amount of energy in Joules.
m is the amount of mass in kilograms.
c is the speed of light, in meters per second (299,792,458).
Now, as for E=hv, this doesn't give you the energy of a photon in this situation. What it does, is derive the energy from the wavelength of the photon. For our purposes, the wavelength is pretty irrelevant, but since you brought it up, I may as well define it:
h is Planck constant, expressed in Joules per second (6.62606957(29)×10^-34).
v is the wavelength of the photon.
In the case of matter-antimatter annihilation, the amount of mass lost will be the same as the amount of mass involved. If you throw 1 gram of matter into 1 gram of antimatter, the total emitted energy will be equal to 179,751,035,747,363.528 Joules, or 2 grams of matter.
So once again, the only equation you need to derive the amount of mass lost from any reaction (assuming perfect efficiency, which only exists with matter-antimatter annihilation so far*) is E=mc^2. Plug in the amount of energy gotten, then derive the amount of mass lost.
*This stage is pretty simply, you simply multiply the energy by the efficiency expressed as 1/n before plugging it into E=mc^2.
7slaterj
21st November 2011 - 07:45 PM
yeh i know all that, i put up a new question if ya wanna help me out there please
MjolnirPants
21st November 2011 - 09:00 PM
QUOTE (7slaterj+Nov 21 2011, 02:45 PM)
yeh i know all that, i put up a new question if ya wanna help me out there please
Your new question contains the e=hv formula. Unless you're trying to calculate wavelength, it's wrong.
Confused1
21st November 2011 - 11:49 PM
To (maybe) reduce confusion:-
E=hν where ν is a Greek character (Nu) is probably best written as:-
E=hf [ where E is energy, h is Planck's constant and f is frequency ]
Planck's constant has the dimensions of Joule.s (Joule seconds not Joules per second)
-C2
Robittybob1
22nd November 2011 - 12:50 AM
QUOTE (Confused1+Nov 21 2011, 11:49 PM)
To (maybe) reduce confusion:-
E=hν where ν is a Greek character (Nu) is probably best written as:-
E=hf [ where E is energy, h is Planck's constant and f is frequency ]
Planck's constant has the dimensions of Joule.s (Joule seconds not Joules
per second)
-C2
But have you thought of what happens when a photon of the right frequency combines with an electron and puts it into another orbital. What does the extra energy do? Does it get more Kinetic Energy (KE)? Does it get more momentum? Does it get more mass? Does it get more of something else?
7slaterj
22nd November 2011 - 11:21 AM
new post has different equation, looks more correct lol
Im confused with this post now, has too many questions and misunderstandings, everone discuss on the new one, "mass loss"
MjolnirPants
22nd November 2011 - 07:37 PM
QUOTE (Confused1+Nov 21 2011, 06:49 PM)
To (maybe) reduce confusion:-
E=hν where ν is a Greek character (Nu) is probably best written as:-
E=hf [ where E is energy, h is Planck's constant and f is frequency ]
Planck's constant has the dimensions of Joule.s (Joule seconds not Joules
per second)
-C2
You are correct.
I need to proof-read my posts more thoroughly.
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