there are 2 part for this problem I got the part one but i didnt get another one so helpppp please.......

1)A 44.4 kg box initially at rest is pushed 5.3m along a rough, horizontal floor with a constant applied horizonta force of 181.646N.
The acceleration of gravity is 9.8 m/s2.
If the coefficient of friction between box and floor is 0.38, find the work done by the friction. Answer in units of J.
The answer for this question is -876.33

2) find the final speed of the box. Answer UNits of m/s. Please help me in this problem....post the reply as soon as possible if u can.......

Hi

The total force experienced by the box is going to be the forward force applied by the pushing minus the opposing force of friction. Once you find the net force on the box, you can use the F=ma equation to solve for a. From there you can use the kinematic equations to find the final velocity.