Thermodynamics

3fingers

8th January 2010 - 09:02 AM

Ideal gas goes from situation 1, to 2, to 3 in two steps with T0=240K

1st step:
p1=p2=2*10^5 [Pa]
V1=5 [l]
V2=15 [l]

2nd step:
p2=2*10^5 [Pa]
p3=1*10^5 [Pa]
V1=V2=15 [l]

question: find Work, Internal Energy and Heat Transfer

I know delta W=p*dV=2000J (correct?)
and I know delta Q = delta W + dU
but how can I find dU?

anacephal

14th January 2010 - 11:09 PM

For an ideal gas U=(3/2)n R T where n is the number of molls.

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