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Iori Fujita

Let's change the Einstein field equation a bit.
Einstein original Rab - 1/2 * Rgab = 8paiG/c^4 * Tab
Modified version Rab - 1/2 * Rgab = 8paiG/c^4 * (Tmab + i*Teab)
Here: Tmab is the stress tensor by matter
Teab is the energy tensor by emission energy
Then this should be the Modified Einstein Field Equation (MEFE).

http://www.geocities.jp/imyfujita/galaxy/galaxy01.html
Iori Fujita



AlphaNumeric
I could have sworn I responded to a post identical to this in recent days. Did you delete it?

I'll repeat what I said :

You offer no reason to include a complex term.
You don't check to see if it gives viable physics.
The manifold in GR is real, not complex.
Taking real and imaginary parts reduces your equation to :

Rab - 1/2 * Rgab = 8paiG/c^4 * (Tmab)
0 = Teab

Utterly pointless. This is because the LHS is real since the manifold is real. Though sometimes tells me you don't understand complex differential geometry.

You've been saying this for months, if not years, and in all that time haven't bothered to learn any GR or differential geometry. Heck, given you don't even check to see what taking real and imaginary parts gives you, it would seem you don't even properly grasp complex numbers!
Iori Fujita
The Law of Universal Gravitation and Separation

It is the universal force which unifies gravity and separator into one. No one ever knows about the separator force. So now, I give a definition of the law of universal separation at first.

Fs = - Sp Ea Eb / r^2 F ; the separation force
Ea ; Energy which belongs to the point a
Eb ; Energy which belongs to the point b
r ; the distance between a and b
Sp ; the separation constant
This force will not be detected on the Earth. It can be negligible even in the solar system. But it will work in the galactic scale.
Next step is to unify Gravitation and Separation into one law.

Fg = G Ma Mb / r^2 -----------------Then,
Fg+s = G Ma Mb / r^2 - Sp Ea Eb / r^2


And assume that Sp = G / c^4, because E = mc^2.

Fg+s = G Ma Mb / r^2 - (G / c^4) Ea Eb / r^2

One step forward by using the complex number formula.

F = G ( Ma + i Ea / c^2 ) ( Mb + i Eb / c^2 ) / r^2
F = G Ma Mb / r^ - (G / c^4) Ea Eb / r^2 + i ( G Ea Mb / ( r^2 c^2 ) + G Ma Eb / ( r^2 c^2 ))
The real part is Re( F ) = Fg+s, but I don't know how to deal with the imaginary part ; Im( F ) = G Ea Mb / ( r^2 c^2 ) + G Ma Eb / ( r^2 c^2 ).

So an existing substance is to be described as S = M + i E / c^2 .
In a certain independent area, if M + E / c^2 = constant ( in other words when M decreases by ΔM, E will increases by ΔE = ΔM c^2 ), then abs( S ) = will be minimum when M = E / c^2, because abs( S ) = root( M^2 + E^2 / c^4 ).

Iori Fujita
AlphaNumeric
Obviously you don't want to accept my criticism so you ignore it.
barakn
QUOTE (Iori Fujita+Jun 10 2008, 02:13 PM)
I don't know how to deal with the imaginary part

That was already very obvious.
Beer w/Straw
QUOTE (AlphaNumeric+Jun 11 2008, 04:53 AM)
Obviously you don't want to accept my criticism so you ignore it.

I ignored your criticism too!


But only after I ignored the post it was criticising.
Iori Fujita

It is said by all the people that the gravity has the same intensity regardless of the direction of measurement and that it is isotropic. But I think that the gravity will work not only three dimensionally but also two or one dimensionally. In the two or one dimensional gravity, the gravity will be concentrated in one plane or line and will have a stronger effect than three dimensional gravity has. Then the separation forces are necessary in order to smash the gravity into two or one dimension.
Then the imaginary factor is necessary.
Iori Fujita
shalayka
QUOTE (Iori Fujita+Jun 12 2008, 09:52 PM)
It is said by all the people that the gravity has the same intensity regardless of the direction of measurement and that it is isotropic. But I think that the gravity will work not only three dimensionally but also two or one dimensionally. In the two or one dimensional gravity, the gravity will be concentrated in one plane or line and will have a stronger effect than three dimensional gravity has. Then the separation forces are necessary in order to smash the gravity into two or one dimension.
Then the imaginary factor is necessary.
Iori Fujita


Not everyone believes that the gravitational attraction is necessarily isotropic -- considering even the Solar System, each planet emits gravitational waves away from the Sun. That automatically makes the gravitational potential of each planet anisotropic (though barely).

Cooperstock & Tieu have written some stuff about nonlinear gravitation.

I've been working on a similar line of thought for the past year. My method does not require an imaginary factor, and the result is that all forms of interaction are bunched into a single framework -- including dark matter and dark energy.
AlphaNumeric
QUOTE (Iori Fujita+Jun 12 2008, 10:52 PM)
n the two or one dimensional gravity, the gravity will be concentrated in one plane or line and will have a stronger effect than three dimensional gravity has.

Demonstrably false.
QUOTE (Iori Fujita+Jun 12 2008, 10:52 PM)
Then the imaginary factor is necessary.
Then you know nothing about geometry. The Schwarzchild metric, which describes the gravitational field of spherical objects, is easily extendable to more dimensions. It remains a function of Real numbers. ALL physical quantities are Real. What is the physical effect of 'i metres per second per second acceleration'? It's meaningless.

I told you months ago that relativity is based on a real manifold. You didn't bother to look up what that means did you?

What do you actually know of relativity?
QUOTE (shalayka+Jun 12 2008, 10:52 PM)
considering even the Solar System, each planet emits gravitational waves away from the Sun. That automatically makes the gravitational potential of each planet anisotropic (though barely).
Wrong. A perfectly isotropic system (ie spherically symmetric) doesn't make gravitational waves. It's an elementary result of differential geometry.

Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves.

They emit them in a direction which is due to their perturbation away from spherical symmetry. It's not that they emit them away from the Sun, that's wrong.

Do you know any relativity? It doesn't seem so, but you don't see anything wrong with making up what you know to be lies.

It's pretty pathetic that you and Iori do that. Are you do stupid and desperate that you cannot learn even the basics of relativity, despite, in Iori's case, having been told precisely the results to look at?

Utterly pathetic. Both of you.
shalayka
QUOTE (AlphaNumeric+Jun 12 2008, 11:34 PM)
Demonstrably false.
Then you know nothing about geometry. The Schwarzchild metric, which describes the gravitational field of spherical objects, is easily extendable to more dimensions. It remains a function of Real numbers. ALL physical quantities are Real. What is the physical effect of 'i metres per second per second acceleration'? It's meaningless.

I told you months ago that relativity is based on a real manifold. You didn't bother to look up what that means did you?

What do you actually know of relativity?
Wrong. A perfectly isotropic system (ie spherically symmetric) doesn't make gravitational waves. It's an elementary result of differential geometry.

Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves.

They emit them in a direction which is due to their perturbation away from spherical symmetry. It's not that they emit them away from the Sun, that's wrong.

Do you know any relativity? It doesn't seem so, but you don't see anything wrong with making up what you know to be lies.

It's pretty pathetic that you and Iori do that. Are you do stupid and desperate that you cannot learn even the basics of relativity, despite, in Iori's case, having been told precisely the results to look at?

Utterly pathetic. Both of you.

Alphanumeric,

Even a spherically symmetric body will emit gravitational waves in the direction opposite of acceleration. This is a basic result of the finite propagation speed of change in the metric. If you don't understand this, look up braking radiation. It's similar in concept.

An axisymmetric body will not emit gravitational waves simply due to rotation on its axis. Why would it? There is no change in the metric over time. Have you not studied the Kerr metric and (more importantly) its Killing vectors? And don't bother counting the asymmetry due to you, me, the Empire State Building or Mount Everest. Those contributions are obviously unimportant in the grand scheme.

You have it very much backwards. And you're an ***.

If you're an actual physicist, then thank God I'm not.
AlphaNumeric
QUOTE (shalayka+Jun 13 2008, 04:42 PM)
Even a spherically symmetric body will emit gravitational waves in the direction opposite of acceleration. This is a basic result of the finite propagation speed of change in the metric. If you don't understand this, look up braking radiation. It's similar in concept.
If a star 'pulses', so that r = r(t) then it won't emit radiation. If it's rotating, then it won't emit radiation, by symmetry analysis of the metric.

A planet orbitting a star will (the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric. Typical analysis of orbits, like infalling objects to back holes, don't consider the back reaction of the infalling object on the space-time. If you're being ultra precise then you need to consider this even for the Earth. NASA simulations show how complicated full back reaction calculations are.

But a perfectly spherically symmetric system will not emit gravitational radiaction, even if it's a system whose fundamental radius is varying in time.

http://relativity.livingreviews.org/open?p...articlesu5.html
QUOTE (shalayka+Jun 13 2008, 04:42 PM)
An axisymmetric body will not emit gravitational waves simply due to rotation on its axis. Why would it? There is no change in the metric over time. Have you not studied the Kerr metric and (more importantly) its Killing vectors? And don't bother counting the asymmetry due to you, me, the Empire State Building or Mount Everest. Those contributions are obviously unimportant in the grand scheme.

The Kerr metric is spherically symmetric. It's the spherically symmetric rotating solution to the Einstein Field Equations.

Perturbations from that will result in gravity waves. The perturbations take several forms, scalar, vector and tensor. Each of them alters the metric in a specific way, some of them time varying. Obviously there has to be some kind of asymmetry in time or space, thus invalidating the usual Killing vectors. You can see this by assuming a linear linear pertubation of the metric, ie G_ab = g_ab + h_ab where g_ab I define to be some set constant metric, typically the flat one. Computing the Riemann curvature tensor to linear order in h leads you to two things. A simple form for the tensor and the D'donder gauge for h. From here you get the wave equation for h_ab perturbations.
QUOTE (shalayka+Jun 13 2008, 04:42 PM)
You have it very much backwards. And you're an ***.

If you're an actual physicist, then thank God I'm not.
Actually black holes was a course I got a distinction in and linearisation of the curvature tensor for derivation of gravity waves was a question I answered in my 4th year exam for GR. And my black holes lecturer was an ex-student of Hawking.
shalayka
QUOTE (AlphaNumeric+Jun 13 2008, 05:29 PM)
If a star 'pulses', so that r = r(t) then it won't emit radiation. If it's rotating, then it won't emit radiation, by symmetry analysis of the metric.

A planet orbitting a star will (the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric. Typical analysis of orbits, like infalling objects to back holes, don't consider the back reaction of the infalling object on the space-time. If you're being ultra precise then you need to consider this even for the Earth. NASA simulations show how complicated full back reaction calculations are.

But a perfectly spherically symmetric system will not emit gravitational radiaction, even if it's a system whose fundamental radius is varying in time.

http://relativity.livingreviews.org/open?p...articlesu5.html

The Kerr metric is spherically symmetric. It's the spherically symmetric rotating solution to the Einstein Field Equations.

Perturbations from that will result in gravity waves. The perturbations take several forms, scalar, vector and tensor. Each of them alters the metric in a specific way, some of them time varying. Obviously there has to be some kind of asymmetry in time or space, thus invalidating the usual Killing vectors. You can see this by assuming a linear linear pertubation of the metric, ie G_ab = g_ab + h_ab where g_ab I define to be some set constant metric, typically the flat one. Computing the Riemann curvature tensor to linear order in h leads you to two things. A simple form for the tensor and the D'donder gauge for h. From here you get the wave equation for h_ab perturbations.
Actually black holes was a course I got a distinction in and linearisation of the curvature tensor for derivation of gravity waves was a question I answered in my 4th year exam for GR. And my black holes lecturer was an ex-student of Hawking.

You're completely missing the point. A stationary spherically (or axi-) symmetric body does not undergo acceleration. Planets obviously are not stationary, since they undergo continuous acceleration. This obviously results in a change in the metric over time.

You mentioned rotation and the resulting bulge. Sorry for bringing up the Kerr metric. I just needed to point out to you that an axisymmetric body does not emit gravitational radiation just because it rotates. There is no change in the metric over time.

It doesn't need to get any more complicated than "a change in the metric". If it's time symmetric, then there is no chance for radiation. If the spinning (or non-spinning) body is axisymmetic (or spherically symmetric), there is no chance for time asymmetry.

For you to bring up all that extra crap is just typical handwaving. Especially perturbations, considering you're the one who initially imposed the axisymmetic shape at the root of this discussion. For the third time: It's impossible for a stationary axisymmetric body spinning along the axis of symmetry to perturb spacetime. That would require a change in energy density at any one point in space. That obviously does not happen since the body is symmetric, ex: the object is completely identical under any amount of rotation along the axis of symmetry. That's the very definition of axisymmetric.

As for pulsating stars, maybe brush up on Newton's shell theorem before even starting on relativistic treatment.

I'm a student of Misner, Thorne and Wheeler. Three name drops are better than one, right?
shalayka
I found a nice PowerPoint/PDF file for you to review.

"Gravity Wave Hunt"
http://www.physics.mcmaster.ca/phys3a03/

In it you will notice that they focus on gravitational radiation given off by the Earth as it orbits around the Sun -- as I've claimed occurs, and you attempted to refute.

It also mentions binary pulsars, and black holes. These also give off gravitational radiation in the same manner, ex: acceleration of a mass causes gravitational waves traveling away from the gravitational barycentre.

Hope that settles it for you. If not, write to the professor that ran the course and argue with him. For surely a PhD cannot be wrong, in your opinion -- for however little that's now worth.
AlphaNumeric
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
A stationary spherically (or axi-) symmetric body does not undergo acceleration.

That's inline with what I said. The Kerr metric isn't a valid metric for planets. It's because they are too extended and you find their physical properties aren't symmetric enough, the Kerr metric is spherically symmetric on it's event horizon.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
Planets obviously are not stationary, since they undergo continuous acceleration. This obviously results in a change in the metric over time.
Also what I said. Or did you not understand the section of my post on back reactions?
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
Sorry for bringing up the Kerr metric.
Nice back peddling.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
I just needed to point out to you that an axisymmetric body does not emit gravitational radiation just because it rotates. There is no change in the metric over time.
For the second time, the Kerr metric is not axisymmetric only, it's spherically symmetric about it's event horizon.

The Zeroth Law of Black Hole mechanics ring a bell?
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
For you to bring up all that extra crap is just typical handwaving.
No, it isn't. There's only 3 ways a metric can be perturbed, scalar, vector and tensor. This is practically a tautology. These perturbations result in specific effects on the system, the link I provided even goes into details. I can provide more details if you wish, including specific derivation of the effects of each kind of perturbation. It's enough to warrant an entire section in my lecture notes.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
Especially perturbations, considering you're the one who initially imposed the axisymmetic shape at the root of this discussion.
No, I didn't. I talked about perturbations from symmetry. And you're the one who doesn't even understand the Kerr metric is spherically symmetric, despite me telling you several times.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
For the third time: It's impossible for a stationary axisymmetric body spinning along the axis of symmetry to perturb spacetime. That would require a change in energy density at any one point in space. That obviously does not happen since the body is symmetric, ex: the object is completely identical under any amount of rotation along the axis of symmetry. That's the very definition of axisymmetric.
Well done on repeating what I said.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
As for pulsating stars, maybe brush up on Newton's shell theorem before even starting on relativistic treatment.
Obviously you didn't understand what I said. The pulsating star is spherically symmetric all the time. Therefore it doesn't break the symmetry. Therefore it doesn't emit gravitational waves, despite it's metric being time dependent. The form of variation in a metric must be of a particular kind. As I said, I can provide details.

And I know about Newton's Shell Theorem. It's mentioned in my 1st year courses on Newtonian dynamics and vector calculus. I now teach it. I have also explained it to people here, on this forum.

Obviously it's over your head to understand anything than repeat definitions.
QUOTE (shalayka+Jun 13 2008, 06:53 PM)
I'm a student of Misner, Thorne and Wheeler. Three name drops are better than one, right?
In other words you used a particular textbook.

I took 2nd year special relativity under Ruth Williams. I took 3rd year asymptotic methods under Peter D'eath. I took 3rd year GR under Gary Gibbons. I took 4th year GR under John Stewart. I took 4th year black holes under Malcolm Perry. They are all part of The Cambridge Relativity Group. I now do a string theory PhD on compact dimensions.

If you're including textbooks then I'm also a student of Schutz, Wald, Misner, Wheeler and Thorne and Stewart (again).

Enough name dropping for you?
MjolnirPants
QUOTE (shalayka+Jun 13 2008, 05:53 PM)
A stationary spherically (or axi-) symmetric body does not undergo acceleration.

Not always true.
Equivalence Principle
Technically, not ever true, since there's really no such thing as "stationary."
O course, if we're assumin this body ain't in a gravitational field, then yer right, ya jes phrased it really badly, son.
Ya shoulda said "A non-inertial spherically symetric body does not undergo acceleration."

QUOTE
Sorry for bringing up the Kerr metric. I just needed to point out to you that an axisymmetric body does not emit gravitational radiation just because it rotates. There is no change in the metric over time.

The Kerr Metric is spherically symetric.

QUOTE (->
QUOTE
Sorry for bringing up the Kerr metric. I just needed to point out to you that an axisymmetric body does not emit gravitational radiation just because it rotates. There is no change in the metric over time.

The Kerr Metric is spherically symetric.

For you to bring up all that extra crap is just typical handwaving.

No, it ain't. I ain't never seen this man do any arm-wavin, an I've read through his postin history pretty thoroughly. Lotta knowledge in there, you should try it.

QUOTE
As for pulsating stars, maybe brush up on Newton's shell theorem before even starting on relativistic treatment.

Shperically symmetric body's don't emit gravitationa waves, son.

QUOTE (->
QUOTE
As for pulsating stars, maybe brush up on Newton's shell theorem before even starting on relativistic treatment.

Shperically symmetric body's don't emit gravitationa waves, son.

I'm a student of Misner, Thorne and Wheeler.

Liar. Ya'd know better than to say some o the things ya've said if ya were.


EDIT: Sorry AN, didn't mean to butt in!
shalayka
QUOTE (AlphaNumeric+Jun 13 2008, 08:29 PM)
That's inline with what I said.


No, you denied that the Earth radiates gravitational waves because it's in orbit.

You said that the gravitational waves are from its asymmetries.

Clearly there are asymmetries, but they contribute practically nothing compared to that given off by its orbit-related acceleration.

All the other crap you brought up is just unrelated nonsense to muddy the issue that you were completely wrong.
MjolnirPants
QUOTE (shalayka+Jun 13 2008, 08:45 PM)
The truth of the matter is that you denied that the Earth radiates gravitational waves because it's in orbit. You said that the gravitational waves are from its asymmetries. Clearly there are asymmetries, but they contribute practically nothing compared to that given off by its orbit-related acceleration.

All the other crap you brought up is just unrelated nonsense to muddy the issue that you are completely wrong.

Acceleration is asymmetric.
biggrin.gif
Nice try, though. laugh.gif
shalayka
QUOTE (MjolnirPants+Jun 13 2008, 08:48 PM)
Acceleration is asymmetric.
biggrin.gif
Nice try, though. laugh.gif

"Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves."

Enough said. You claimed that the gravitational radiation was from axisymmetric bulge, and not because of orbit.

And no, acceleration is not asymmetric by definition. This goes back to the case of the pulsating star. Like I said, check out Newton's shell theorem for a brush up on the special case of spherical symmetry.
MjolnirPants
QUOTE (shalayka+Jun 13 2008, 08:50 PM)
And no, acceleration is not asymmetric by definition. This goes back to the case of the pulsating star. Get it right.

What, time don't count?
Or is an acceleratin body movin the same speed now that it were 10 seconds ago? laugh.gif

EDIT: In defence of AN, I offer the followin:

QUOTE (AN+)
A planet orbitting a star will [give off gravitational waves](the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric. Typical analysis of orbits, like infalling objects to back holes, don't consider the back reaction of the infalling object on the space-time. If you're being ultra precise then you need to consider this even for the Earth. NASA simulations show how complicated full back reaction calculations are.

followed by:
QUOTE
No, you denied that the Earth radiates gravitational waves because it's in orbit.

shalayka
QUOTE (MjolnirPants+Jun 13 2008, 08:53 PM)
What, time don't count?
Or is an acceleratin body movin the same speed now that it were 10 seconds ago? laugh.gif


If it's in circular orbit, then yes, it would be moving at the same speed after 10 seconds. Obviously the direction would be changed (unless a full orbit takes exactly 10 seconds).
MjolnirPants
QUOTE (shalayka+Jun 13 2008, 08:55 PM)
If it's in circular orbit, then yes, it would be moving at the same speed after 10 seconds. Obviously the direction would be changed (unless a full orbit takes exactly 10 seconds).

laugh.gif laugh.gif

Do ya understand what makes orbital trajectories a form o acceleration?
The earth's speed around the sun might be constant as a whole but the direction in which it's movin is constantly changin, meanin it's speed in any given direction around it's orbit is constantly changin.

I jes edited my last post, go read it biggrin.gif
shalayka
QUOTE (MjolnirPants+Jun 13 2008, 08:58 PM)
laugh.gif laugh.gif

Do ya understand what makes orbital trajectories a form o acceleration?
The earth's speed around the sun might be constant as a whole but the direction in which it's movin is constantly changin, meanin it's speed in any given direction around it's orbit is constantly changin.

I jes edited my last post, go read it biggrin.gif


Dude, you mean its velocity changes, not its speed. Velocity is speed + direction.

So yes, its speed remains constant, but its direction and velocity do not. You asked if its speed remains constant, not its velocity. Not that I see the point.

Either way, I'm out of here guys. Thanks for the chat. It was very illuminating.
AlphaNumeric
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
No, you denied that the Earth radiates gravitational waves because it's in orbit.

No, I talked about the Earth's gravitational field. I specifically said the Earth's orbital motion in the Sun's gravitational field creates a back reaction on the space-time which emits a couple of kilowatts of power.

Did you miss that? Or are you just ignoring it deliberately.

The Kerr (or any other such exact solution to the EFEs) is about an isolated object. 'Orbits' about them are calculated using 'test particles' which don't alter the gravitational field, ie no back reaction. If you want to discuss the effect the Earth's gravitational field has on the Sun's field you are presupposing the back reaction ISN'T zero. Then you are perturbing the metric of the Sun and you get into the perturbation theory of metrics. Precisely what I mentioned.
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
Clearly there are asymmetries, but they contribute practically nothing compared to that given off by its orbit-related acceleration.
I never said otherwise.
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
All the other crap you brought up is just unrelated nonsense to muddy the issue that you were completely wrong.
So a link to a website which derived energy output in an isolated system using the metric perturbations I talked about is 'muddying the issue'? laugh.gif

Also, you tried to trump my sources. I trumped yours. Now you don't want to play any more.
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
"Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves."
You obviously don't understand context. If you're talking about the metric of the Earth you assume it's isolated. Then the only gravitational wave production is from it's isotropy. This comes from specific deviations from it's spherical symmetry.

If you talk about gravitational waves due to the metric of the Sun, you assume it's isolated. Then the only gravitational wave production is from it's isotropy. This comes from specific deviations from it's spherical symmetry.

If you want to talk about the interaction of the two gravitational fields then you should say so because it's an entirely different kettle of fish. Then the output is due to the motion of the Earth about the Sun, which is a symmetry breaking effect and is going to cause a 'flow' of some physical quantity somehow. In this case energy out from the system in an attempt to right the asymmetry (the orbit is slowed and the planet spirals into the star).

Earth only gravitational waves = derivation from symmetric state. Sun only gravitational waves = derivation from symmetric state. Earth-Sun gravitational waves = orbital motion. This is just a weaker (MUCH weaker) situation than observed pulsar orbits which are measurably decaying due to supposed gravitational wave emission.
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
And no, acceleration is not asymmetric by definition. This goes back to the case of the pulsating star.
Are you saying oscillating spheres aren't accelerating? laugh.gif
QUOTE (shalayka+Jun 13 2008, 09:45 PM)
Like I said, check out Newton's shell theorem for a brush up on the special case of spherical symmetry.
Because Cambridge graduates in physics don't know that and postgrad supervisors in vector calculus don't know it. rolleyes.gif

Oh and here's my section of lecture notes on the laws of black hole mechanics : http://www.hep.phys.soton.ac.uk/~g.j.weath...s/Mechanics.pdf
shalayka
QUOTE (AlphaNumeric+Jun 13 2008, 09:02 PM)
Are you saying oscillating spheres aren't accelerating?  laugh.gif
Because Cambridge graduates in physics don't know that and postgrad supervisors in vector calculus don't know it.  rolleyes.gif

OK, let me spell it out for you:

Take a spherically symmetric star, and reduce its radius by half over arbitrary time. Ensure that the collapse occurs in a spherically symmetric fashion.

Newton's shell theorem and the Schwarzschild solution both conclude that the vacuum potential/metric outside of the body remains constant. No change in metric, no gravitational waves.

The rest of your posts are of no consequence, since you obviously should already know that this is the most complex it needs to get. Your attempts to further complicate the issue are pointless.

Like you said in the first place, the source of the gravitational waves are the axisymmetric bulge of the Earth exclusively (and so, not due to its orbit). This is obviously completely false.
AlphaNumeric
QUOTE (shalayka+Jun 13 2008, 10:12 PM)
OK, let me spell it out for you:

Take a spherically symmetric star, and reduce its radius by half over arbitrary time. Ensure that the collapse occurs in a spherically symmetric fashion.

Newton's shell theorem and the Schwarzschild solution both conclude that the vacuum potential/metric outside of the body remains constant. No change in metric, no gravitational waves.

Exactly what I said. You don't have to spell it out, I actually ****in' said that. Or didn't you understand "The pulsating star is spherically symmetric all the time. Therefore it doesn't break the symmetry. Therefore it doesn't emit gravitational waves, despite it's metric being time dependent. "?
QUOTE (shalayka+Jun 13 2008, 10:12 PM)
Like you said in the first place, the source of the gravitational waves are the axisymmetric bulge of the Earth exclusively (and so, not due to its orbit). This is obviously completely false.
No, I didn't say that. You're having to lie. It's pathetic.
Iori Fujita

"Energy" is the emission of light. In the beginning there was only the light with the energy ( = Eo ). At present equilibrium, the total matter in the space is (1/2)Eo/c^2 and the total energy has decreased to (1/2)Eo.
Iori Fujita
http://www.geocities.jp/imyfujita/galaxy/galaxy01.html
AlphaNumeric
Iori, you didn't answer my question. Have you actually done relativity? Do you know the difference between differential geometry on a real manifold and one involving complex numbers? Do you even know differential geometry?

What have you learn GR from?
MjolnirPants
QUOTE (shalayka+Jun 13 2008, 08:59 PM)

Dude, you mean its velocity changes, not its speed. Velocity is speed + direction.

So yes, its speed remains constant, but its direction and velocity do not. You asked if its speed remains constant, not its velocity. Not that I see the point.

Either way, I'm out of here guys. Thanks for the chat. It was very illuminating.

Sorry, I assumed from yer posts that ye don't speak physics-jargon. I mean, ya never used it very well before. That's why I explained it to ya in laymans terms instead o simply linkin ya to the wiki article on centripedal force wink.gif I had a feelin ya wouldn't get the connection.
So ya pointed out me own poor physics language, great job. Ya gonna argue my point at all, or jes admit you was wrong?
smile.gif
Iori Fujita
According to the Einstein Theory;
Matter warps the continuum according to the amount (or mass) which exists in any locality. Then all motion along world lines in the vicinity must follow the warp.If world lines must follow warps in space, beams of light passing near the mass should be deflected with a certain angle.
But here for me, the light can't be deflected one-sidedly. It should also affect back the gravity field. Beams of light will loosen the gravity field to the orthogonal direction slightly. And huge amount of beams of light or emissions will shove away the gravity field in a thin-depth disk.
Iori Fujita
AlphaNumeric
QUOTE (Iori Fujita+Jun 15 2008, 01:51 AM)
But here for me, the light can't be deflected one-sidedly. It should also affect back the gravity field.

This is the back reaction I mentioned earlier in the thread. It's taken into account in the T_ab tensor in the EFE. However, for photons the contribution is typically so small that it can be neglected for physical purposes, but it is taken into account if you want to describe it. Nothing to do with factors of i at all.
QUOTE (Iori Fujita+Jun 15 2008, 01:51 AM)
Beams of light will loosen the gravity field to the orthogonal direction slightly.
Can you show this rigorously? I assume that you can show that the spacial projection of the 4-momentum of the photon is orthogonal to the spacial perturbation to the geodesics?
QUOTE (Iori Fujita+Jun 15 2008, 01:51 AM)
And huge amount of beams of light or emissions will shove away the gravity field in a thin-depth disk.
Can you show this rigorously? I assume you can show that in the limit of infinite photons the space-time geometry tends to a flat disk? For instance, the metric of say a star ends up losing spherical symmetry and the field strength gets suppression in sin(theta) where theta is the azimuthal angle?

Because if you cannot show it, you have no basis to claim that particular result comes from relativity. But then you ignored my question about how you know relativity. Books? Lectures? Websites? Are you afraid to admit you've never studied it?
Iori Fujita
There are three phases of the relation of gravitation and separation.

elliptical galaxy e.g. NGC4881 "Three Dimension" -> ordinary Newton's equation
GM(<r)m/r^2 = mv^2/r
gravitationally unstable

barred spiral galaxy e.g.NGC1300 "One Dimension" -> new New1ton's equation
G''M(<r)m = mv^2/r

spiral galaxy e.g. NGC4414 "Two Dimension" -> new New2ton's equation
G'M(<r)m/r = mv^2/r
gravitationally stable

There are also phase-shifts among those three phases.

Iori Fujita

philip347
I hate to say this, but I think Lori Fujita, is a made up name and what's really in back of Lori Fujita, is a super computer.
Fujitsu of Japan, made the first primitive main frame super calculating computers.

So it follows name sake suit, that they would make up an anagram, that of course would put men's minds below the belt.I mean your thinking Lori Fujita, your thinking real nice figure, panty pages, honor society, big on campus, but what happens when you enter that name in a search engine?

I don't care.

The only thing Lori Fujita cant answer, is topagrphacalities on advanced races, as this is out of her protocols.

My guess, is that Lori Fujita, is either a person hiding behind something similar to a Gray computer, or is an active artificial intelligence program, structured to add data, into a human like response.
Iori Fujita
The first theory is "The light bends the gravity".
The second theory is "The matter produces the gravity field, and the energy of emission produces the separation field".
Iori Fujita

AlphaNumeric
Iori, is there a reason you're ignoring my questions?
shalayka
QUOTE (AlphaNumeric+Jun 17 2008, 01:08 PM)
Iori, is there a reason you're ignoring my questions?

Dear Dr. Misner,

I have been reading about gravitational waves in your MTW book.

During a discussion with someone, they informed me that the gravitational waves emitted by the Earth are because it is a rotating axisymmetric object, and not because the Earth is moving through space as it orbits around the Sun.

This doesn't sound quite right to me.

Are gravitational waves emitted by the Earth as it is continually accelerated by the Sun's gravitational field? Since the metric of the Solar System is continually changing due to Earth's changing position and direction of motion, I would think that there are gravitational waves due to this.

If the Earth were static in shape and density, perfectly axisymmetric (no mountains or lopsided magnetic fields), and rotating along its axis of symmetry, would it emit gravitational waves at all? Since the metric surrounding this body would be static, I would think that there are not gravitational waves.

Thank you for any time and interest that you can provide. Any clarification for us is always greatly appreciated.

Sincerely yours,
Shawn Halayka


Dr. Misner:
"You are correct. To the extent that the Earth is a symmetric object rotating about its symmetry axis, no gravitational waves are produced. Asymmetries about the rotation axis could lead to waves with a 12 hour period. The motion of the Earth around the Sun will produce (very weak) gravitational waves with a period of 6 months, but these first show their wavelike character at distances beyond a few light years from the Sun."
-- Misner


shalayka:
So, for all intents and purposes the Earth is symmetric around its axis of rotation, and so the gravitational waves caused by Mount Everest are all but practically non-existent. It is the motion of the Earth in orbit that gives off the only non-negligible gravitational wave energy, even though it is still very weak and with an enormous period of time between each wave.

In effect, any time-dependent change in the metric results in gravitational waves. Oppositely, any axisymmetric body rotating on its axis of symmetry does not induce a change in the metric. This is simply because the density of mass-energy at any point in space does not change between instants of time -- this is the very definition of an axisymmetric body rotating on its axis of symmetry.

Good to know.

Alphanumeric, the next time you want to correct me, check with your advisor first. It will save us both a lot of time, and won't confuse the heck out of those actually trying to learn physics.

At the very least, don't be a jerk if you feel the need to correct someone.

Ditto for you too MjolnirPants.
AlphaNumeric
QUOTE (shalayka+Jun 17 2008, 03:48 PM)
Alphanumeric, the next time you want to correct me, check with your advisor first. It will save us both a lot of time, and won't confuse the heck out of those actually trying to learn physics.

Jesus H Christ, all you've done is just get Misner to confirm what I ****ing said!
QUOTE (shalayka+Jun 17 2008, 03:48 PM)
During a discussion with someone, they informed me that the gravitational waves emitted by the Earth are because it is a rotating axisymmetric object, and not because the Earth is moving through space as it orbits around the Sun.
I did NOT say this. You seem hell bent on ignoring what I specifically said and putting words in my mouth. The Earth produces gravitational waves due to it's rotations due to asymmetries. The Sun produces gravitational waves due to it's rotation due to asymmetries. The Earth's motion around the Sun produces gravitational waves due to it's motion through space-time.

I said this. Hell, I've said it in previous threads here too. You read my comment about the Earth's metric and assumed I was talking about the Sun's gravitational field being altered by the Earth's effect. This is wrong.

For the love of **** you're an idiot. Really, how many times do I have to correct you on your INTERPRETATION of what I said. It was clear from the context what I was talking about. Your ignorance is the problem. Do you want me to quote the posts in this thread or are you capable of reading it yourself?
QUOTE (shalayka+Jun 17 2008, 03:48 PM)
At the very least, don't be a jerk if you feel the need to correct someone.
I'll call someone an idiot if they continue to LIE after I've corrected them.

You are an idiot.
QUOTE (shalayka+Jun 17 2008, 03:48 PM)
In effect, any time-dependent change in the metric results in gravitational waves. Oppositely, any axisymmetric body rotating on its axis of symmetry does not induce a change in the metric. This is simply because the density of mass-energy at any point in space does not change between instants of time -- this is the very definition of an axisymmetric body rotating on its axis of symmetry.
Actually, Misner specifically said the Earth's daily rotation causes gravitational waves. I quote : To the extent that the Earth is a symmetric object rotating about its symmetry axis, no gravitational waves are produced. Asymmetries about the rotation axis could lead to waves with a 12 hour period. The perturbations away from perfect symmetry cause gravitational waves due to the Earth's rotation. AND the orbit of the Earth produces them. EXACTLY what I said.
MjolnirPants
SHALAYKA, READ THIS POST, DON'T IGNORE IT YA COMPLETE 'TARD!

QUOTE
During a discussion with someone, they informed me that the gravitational waves emitted by the Earth are because it is a rotating axisymmetric object, and not because the Earth is moving through space as it orbits around the Sun.

Ya keep sayin this, but we all know it's complete bullcrap. Read these quotes:
QUOTE (->
QUOTE
During a discussion with someone, they informed me that the gravitational waves emitted by the Earth are because it is a rotating axisymmetric object, and not because the Earth is moving through space as it orbits around the Sun.

Ya keep sayin this, but we all know it's complete bullcrap. Read these quotes:
Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves.

They emit them in a direction which is due to their perturbation away from spherical symmetry. It's not that they emit them away from the Sun, that's wrong.

This is what ya keep referrin to, but yer ignorin the fact that it was said in response to you sayin:
QUOTE
considering even the Solar System, each planet emits gravitational waves away from the Sun. That automatically makes the gravitational potential of each planet anisotropic (though barely).

It was only meant to respond to that statement, as common sense shoulda told ya already, if ya had any.

Then this exchange took place:
QUOTE (->
QUOTE
considering even the Solar System, each planet emits gravitational waves away from the Sun. That automatically makes the gravitational potential of each planet anisotropic (though barely).

It was only meant to respond to that statement, as common sense shoulda told ya already, if ya had any.

Then this exchange took place:
QUOTE (Shalayka+)
Even a spherically symmetric body will emit gravitational waves in the direction opposite of acceleration. This is a basic result of the finite propagation speed of change in the metric. If you don't understand this, look up braking radiation. It's similar in concept.


If a star 'pulses', so that r = r(t) then it won't emit radiation. If it's rotating, then it won't emit radiation, by symmetry analysis of the metric.

A planet orbitting a star will [give off gravitational waves] (the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric. Typical analysis of orbits, like infalling objects to back holes, don't consider the back reaction of the infalling object on the space-time. If you're being ultra precise then you need to consider this even for the Earth. NASA simulations show how complicated full back reaction calculations are.

But a perfectly spherically symmetric system will not emit gravitational radiaction, even if it's a system whose fundamental radius is varying in time.

In this one, he clarified himself with regards to the specific issue yer havin now. See the bolded part. Read it a couple o times. Get it through yer head.

Then came this, the beginnins o yer steamin pile o bullcrap argument:
QUOTE
QUOTE (->
QUOTE
That's inline with what I said.



No, you denied that the Earth radiates gravitational waves because it's in orbit.

He never denied that the earth radiates gravitational waves due to it's orbit around the sun.
shalayka
QUOTE (AlphaNumeric+Jun 17 2008, 03:22 PM)
Jesus H Christ, all you've done is just get Misner to confirm what I ****ing said!
I did NOT say this. You seem hell bent on ignoring what I specifically said and putting words in my mouth. The Earth produces gravitational waves due to it's rotations due to asymmetries. The Sun produces gravitational waves due to it's rotation due to asymmetries. The Earth's motion around the Sun produces gravitational waves due to it's motion through space-time.

I said this. Hell, I've said it in previous threads here too. You read my comment about the Earth's metric and assumed I was talking about the Sun's gravitational field being altered by the Earth's effect. This is wrong.

For the love of **** you're an idiot. Really, how many times do I have to correct you on your INTERPRETATION of what I said. It was clear from the context what I was talking about. Your ignorance is the problem. Do you want me to quote the posts in this thread or are you capable of reading it yourself?
I'll call someone an idiot if they continue to LIE after I've corrected them.

You are an idiot.
Actually, Misner specifically said the Earth's daily rotation causes gravitational waves. I quote : To the extent that the Earth is a symmetric object rotating about its symmetry axis, no gravitational waves are produced. Asymmetries about the rotation axis could lead to waves with a 12 hour period. The perturbations away from perfect symmetry cause gravitational waves due to the Earth's rotation. AND the orbit of the Earth produces them. EXACTLY what I said.

The fact of the matter is that I said gravitational waves were caused by its orbital motion, and that the waves travel away from the Sun. Since these waves carry energy-momentum, they create an asymmetry (one side of the field contains more energy than the other). For this you called me a pathetic fraud.

The waves created by the asymmetries of the Earth are unimportant in comparison. How many times do we need to explain this to you? You made it sound like this was the only source that mattered, which in fact, your view was backwards (I've said this before).

Why you felt the need to correct my view is beyond me, since we now appear to be arguing for the same side.

I am not misinterpreting your meaning. If your meaning was initially the same as mine, you wouldn't have said a word, and you certainly wouldn't have called me a pathetic fraud. Give it up.
AlphaNumeric
Just to make sure you don't continue to lie :

http://www.physforum.com/index.php?showtop...ndpost&p=348452
I state Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves.

They emit them in a direction which is due to their perturbation away from spherical symmetry. It's not that they emit them away from the Sun, that's wrong.


In this I am talking about the rotation of the Earth about it's axis. If the Earth is perfectly spherically symmetric then it wouldn't emit gravitational waves due to it's rotation. This is inline with Misner's statement : To the extent that the Earth is a symmetric object rotating about its symmetry axis, no gravitational waves are produced. Asymmetries about the rotation axis could lead to waves with a 12 hour period.

http://www.physforum.com/index.php?showtop...ndpost&p=348583
You state that the gravitational waves of the Earth due to asymmetry can be ignored. But that's what I've been talking about. Misner's comment also says otherwise.

http://www.physforum.com/index.php?showtop...ndpost&p=348625
I explain how a spherically symmetric system can be time varying and still not produce gravitational waves. I also explicitly state A planet orbitting a star will (the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric..

http://www.physforum.com/index.php?showtop...ndpost&p=348739
You claim I denied orbits produce gravitational waves when I explicitly stated otherwise here.

http://www.physforum.com/index.php?showtop...ndpost&p=348747
I then correct you, pointing out how I'd talked about back reaction and even given an order of magnitude amount for the gravitational wave power of the Earth going around the Sun. You seem intent on ignoring this.

http://www.physforum.com/index.php?showtop...ndpost&p=348750
You claim "Like you said in the first place, the source of the gravitational waves are the axisymmetric bulge of the Earth exclusively (and so, not due to its orbit). This is obviously completely false.". No, I was talking about the asymmetry of planets (or stars) from spherical symmetry and rotating about their axis of rotation. That is an issue which is often the cause of confusion, as I've encountered in previous discussions on this matter, while planet orbits around stars is an obvious generation of gravitational waves, particular considering the evidence we have for neutron star orbital decays which is just a more extreme case.

Do a search on these forums, you'll find I've explained gravitational radiation due to orbits to people before. I do NOT think they don't cause gravitational waves. I have explained this numerous times to you now, giving links and sources. You seem intent on ignoring this. I suspect because you have trouble understanding my explainations about tensors, metric perturbations and back reactions.
shalayka
QUOTE (AlphaNumeric+Jun 17 2008, 03:41 PM)
Just to make sure you don't continue to lie :

http://www.physforum.com/index.php?showtop...ndpost&p=348452
I state Planets and all objects emit gravitational waves because of anisotropy, which in the case of the Earth is because it's not a sphere. The Earth (and the Sun and Jupiter etc) bulge at the equator due to rotation. It's that which causes them to emit gravitational waves.

They emit them in a direction which is due to their perturbation away from spherical symmetry. It's not that they emit them away from the Sun, that's wrong.


In this I am talking about the rotation of the Earth about it's axis. If the Earth is perfectly spherically symmetric then it wouldn't emit gravitational waves due to it's rotation. This is inline with Misner's statement : To the extent that the Earth is a symmetric object rotating about its symmetry axis, no gravitational waves are produced. Asymmetries about the rotation axis could lead to waves with a 12 hour period.

http://www.physforum.com/index.php?showtop...ndpost&p=348583
You state that the gravitational waves of the Earth due to asymmetry can be ignored. This is what I'm correcting you on. Misner's comment also says otherwise.

http://www.physforum.com/index.php?showtop...ndpost&p=348625
I explain how a spherically symmetric system can be time varying and still not produce gravitational waves. I also explicitly state A planet orbitting a star will (the Earth gives off something like the order of a kilowatt in such energy loss), but that's because the situation is not symmetric..

http://www.physforum.com/index.php?showtop...ndpost&p=348739
You claim I denied orbits produce gravitational waves when I explicitly stated otherwise here.

http://www.physforum.com/index.php?showtop...ndpost&p=348747
I then correct you, pointing out how I'd talked about back reaction and even given an order of magnitude amount for the gravitational wave power of the Earth going around the Sun. You seem intent on ignoring this.

http://www.physforum.com/index.php?showtop...ndpost&p=348750
You claim "Like you said in the first place, the source of the gravitational waves are the axisymmetric bulge of the Earth exclusively (and so, not due to its orbit). This is obviously completely false.". No, I was talking about the asymmetry of planets (or stars) from spherical symmetry and rotating about their axis of rotation. That is an issue which is often the cause of confusion, as I've encountered in previous discussions on this matter, while planet orbits around stars is an obvious generation of gravitational waves, particular considering the evidence we have for neutron star orbital decays which is just a more extreme case.

Do a search on these forums, you'll find I've explained gravitational radiation due to orbits to people before. I do NOT think they don't cause gravitational waves. I have explained this numerous times to you now, giving links and sources. You seem intent on ignoring this. I suspect because you have trouble understanding my explainations about tensors, metric perturbations and back reactions.

Misner is saying that it's symmetric, not spherically symmetric. Everyone knows there's a bulge. It's assumed.

An axially symmetric body still does not emit gravitational waves. If you place a single mountain on an axisymmetric body, then it's no longer axisymmetric. We are taking the Earth's mountains to be negligible.
AlphaNumeric
QUOTE (shalayka+Jun 17 2008, 04:43 PM)
An axially symmetric body still does not emit gravitational waves. If you place a single mountain on an axisymmetric body, then it's no longer axisymmetric. We are taking the Earth's mountains to be negligible.

Given I was talking about perturbations from symmetry for planets, it was clear I was considering those effects non-negligable, since they were the topic of my posts!

When I then talked about orbits, I said they too produce gravitational waves. I categorically state it. I talk about back reactions. I give a power output for our planet. I give a link to NASA simulations of them.

And yet you persist in your lies.

/edit

And for those who don't post there, shalayka posted this : http://www.sciforums.com/showthread.php?t=82096 Obviously he's really cheesed I called him a liar. I bet he's even more cheesed now that I've pointed out I categorically stated the opposite to what he claims I said, before he emailed Misner and put words on my mouth.
mr_homm
I've been sitting on the sidelines (too busy to post with my Mother in town for her birthday), and watching this develop into a flamefest. At the risk of making ALL parties mad at me, let me jump into the fray here.

This thread has been an exercise in miscommunication from the start. I'm not a mindreader, but I have a pretty clear idea what people were thinking based on their posts (after all, language should be able to express our thoughts with reasonable accuracy, or what's the point?). If you feel I am putting words in your mouth, just say so, and I'll immediately apologize.

Here's how it looks to me:

shalayka posted that planets in the solar system radiate gravitational waves away from the sun, in order to support the point that the gravitational potential is not necessarily isotropic. shalayka never stated what specifically caused this radiation.

AlphaNumeric responded that shalayka was wrong, and to support his point stated that spherically symmetric systems do not radiate gravitationally, that anisotropy is required for gravitational radiation, that planets have equatorial bulges due to rotation, that these bulges cause them to emit gravitational radiation, that the direction of the radiation is controlled by the nature of the anisotropy, and that it is not directed away from the sun.

Both of these posts require major surgery, I'm afraid.

It became clear later that shalayka was discussing gravitational radiation due to the planet's orbital motion around the sun. By stating that the PLANET radiated gravitational waves, he did not explicitly associate the waves with the earth-sun system, which led AN to think he was talking about radiation due to the planet itself. Considering the planet ALONE as the gravitational wave source, such waves could only come from its rotation, which led to AN's making several points about isotropy. This was the first key miscommunication.

However, each post separately has other problems. It looks like AN was initially responding to shalayka's assertion that planets radiate gravitational waves away from the sun, that this was the main point he set out to correct. However, as is his usual style, he baldly stated that shalayka was wrong, then gave commentary, which did not clarify precisely where he thought shalayka was wrong. This left AN's post partly responding to something shalayka actually said ("away from the sun") and partly to something AN thought shalayka meant ("planets radiate").

Now both of these things are actually wrong, so AN was certainly correct in trying to set shalayka straight on them. Let's look at them separately, instead of all muddled up: As to the direction of the radiation, shalayka later stated that it was analogous to braking radiation. This is certainly reasonable, but braking radiation removes energy from an accelerated particle, and hence MUST be directed along the velocity of the particle, rather than opposing the direction of acceleration, so as to carry away forward momentum and also so as to do negative work on the particle. Dropping back from relativity into a Newtonian framework shows clearly that this must be true for gravitational radiation as well, since the same considerations of momentum and energy apply. The braking gravitational radiation is therefore emitted tangent to the planet's orbit, not away from the sun. Of course, AN couldn't give this explanation, because he thought shalayka was not referring to radiation due to orbital motion.

(BTW, when considering the earth-sun SYSTEM, the gravitational radiation clearly causes a loss of angular momentum. The radiation is due to the rotating quadrupole moment of the earth-sun system. The far field radiation pattern can be analyzed based on this quadrupole source, but the near field cannot. The near field pattern shows up as the braking radiation of the earth and that of the sun, which together sum up to give the quadrupole radiation in the far field limit.)

In short, shalayka made one statement that was wrong, and one that seemed wrong.

Unfortunately, AN's responses have several misstatements, which in turn gave shalayka something to jump on in response. AN's statement that a planet's equatorial bulge is what causes it to emit gravitational waves is simply wrong. Although it is no longer spherically symmetric, the planet's bulge is axisymmetric with an axis that coincides with the rotation axis. Another way to say this is that there are gravitational multipole moments, but they are aligned with the axis, so it are time invariant as the planet rotates. Now I'm perfectly sure AN knows this, but the way his post was phrased certainly SEEMED to say that simply by having an equatorial bulge, a spinning planet would radiate.

The whole discussion then gets further and further away from the original dispute. shalayka talks about isolated rotating sources in response to AN's discussion of them, while AN starts talking about back reaction, so they have essentially swapped topics, adding to the confusion. During this discussion, shalayka mentioned the Kerr metric for a rotating body as part of a discussion on why axisymmetric rotating bodies would not radiate (which is what AN SEEMED to dispute in the previous post). AN then picked on the discrepancy between the spherical Kerr solution and the axisymmetric assumption. Here again AN is simply wrong. The Kerr solution does have a spherical event horizon, but the metric itself is not globally spherically symmetric. For instance, the ergosphere is oblate. Once again, I'm sure AN knows this, but his post reads as if he thinks otherwise.

The whole Kerr solution discussion is misguided, because the Kerr solution is a perfectly reasonable far field approximation for an isolated spinning planet, provided there are no surface irregularities aside from the equatorial bulge. The bulge itself does mean that the field differs slightly from a true Kerr solution, but at great distances, the effect of the bulge will become negligible relative to the contribution of the equivalent spherical mass. Radiation is a different story, and would not become negligible at great distances, unless it was already negligible because of the small size of the quadrupole anisotropy. Therefore the whole discussion reverts to the original point that an axisymmetric rotating body will not radiate.

At this point, can we all agree to the following (please?):

An isolated spherically symmetric system cannot radiate.

A spherically symmetric SUBsystem, which is gravitationally interacting with another body to form a larger system, CAN radiate.

The radiation can either be attributed to quadrupole anisotropy in the larger system or to center of mass acceleration in the smaller system, depending on viewpoint.

An isolated, rotating axisymmetric system cannot radiate.

A rotating axisymmetric SUBsystem can, as above, and for the same reasons as the spherical case.

An isolated rotating NEARLY axisymmetric system CAN radiate provided it has nonvanishing quadrupole moment due to mass distribution within the object.

Planets radiate due to their orbital motions AND due to their rotations (provided they are not perfectly axisymmetric).

I would now like to return to the original point shalayka brought up, namely that the gravitational potential might not be isotropic, because of braking radiation. I disagree with this notion, because it seems to be mixing levels. Since the Einstein field equations predict spherically symmetric gravitational effects from spherically symmetric sources, and ALSO predict the braking radiation, it would seem to be unnecessary to build anisotropy into the basis of the theory. The theory already accounts for the observed anisotropy, simply by embedding the planet into a larger system, containing its sun. The anisotropy then arises from the anisotropy of the larger system, and so it is not necessary to postulate directly that the field equations should be anisotropic.

Since relativity, unlike electromagnetism, is not a linear theory, you can't really consider the sun's field in isolation. If this were electromagnetism, with a positive and negative charge instead of sun and earth, you could calculate the field from the positive charge while the negative charge was absent. Then you could insert the negative charge and find the correct force by applying the preexisting field to it. This works because EM is a linear theory. In GR, in contrast, the response of the planet to the sun's field includes the fact that the presence of the planet alters the total field in a nonlinear way. Therefore, it is the NON-LINEARITY of the field equations that gives the APPEARANCE of anisotropy you have mentioned.

As a final note, just in case everyone is not yet mad at me, let me say that both of you have been behaving rather badly. Please read each other's posts with a little more charity and forbearance, and flamefests like this one will not happen. I have not interacted with shalayka before, so I have no idea what his posting history is. He may be 17 kinds of crank and loon in other threads, for all I know. That is not relevant. If one reads his posts without ASSUMING he is an idiot, then one finds that real communication can take place. Likewise, AN has made enough gaffes in this thread that it is necessary to give him the benefit of the doubt as well. Please do so, and you will find him both knowledgeable and even helpful. On both sides of the discussion, if the other person appears to be saying something droolingly insane, perhaps you should ask for clarification before whipping out the straitjacket.

I have no authority on this site, no claim to the moral high ground, and no desire to slap wrists, but PLEASE! The rest of us on this thread have been treated to a show in which one person, who I know is intelligent and well trained, and another person, who I know nothing against, are whacking blindfolded at each other with bats, while the great pinata of truth lies all undiscovered before them. (Ok, that probably has Newton rolling over in his grave. Apologies to Newton.)

--Stuart Anderson

philip347
I don’t like this thread, I’ll tell you why.
First over, Lori Fujita probably does not exist.

If she did, the answers would be like this.

>Well guys, what I’m after here, is to let you know, that through lights travel in space, allot of things happen to it.

What I’m trying to get at here, is that maybe at a distance, light aberates, due to the affect astral bodies place on light as it travels at a distance.

What Einstein brought forwards in his paper on Relativity deals with information before him, as man had to have some proper way of relating to space only.\

There’s none of this. Her answers are cut and dried, socially nonresponsive.This is as in reality she is probably a bunch of sold out process students, who are getting their information directly from a super computer matrix.

They said on the university level, that they were going to do this years ago.

Anytime that you add computer derived data, into a collection of people, its acts as a splinter felon does in the finger and people socially start to argue.

I think that this is what happened in this thread!
MjolnirPants
QUOTE (mr_homm+Jun 17 2008, 07:36 PM)
AN's statement that a planet's equatorial bulge is what causes it to emit gravitational waves is simply wrong. Although it is no longer spherically symmetric, the planet's bulge is axisymmetric with an axis that coincides with the rotation axis.

Yer right on that one. It seemed to me that he was respondin to one wrong point (that spherically symmetric bodies emit gravitational radiation) as well as tryin to show how inertial bodies emit gravitational radiation all in the same sentence, an it got jumbled up. I didn't take issue with it cause it occured to me that the earth ain't jes a sphere with a bulge around the equator. It's got mountains an valleys an oceans, all o which (those what crossed the equator, I mean) would have their contributions to asymmetry magnified by the bulges.

QUOTE
The whole discussion then gets further and further away from the original dispute.  shalayka talks about isolated rotating sources in response to AN's discussion of them,  while AN starts talking about back reaction, so they have essentially swapped topics, adding to the confusion.

That actually cleared up some confusion with me. I was confused, thinkin that AN posted some physics that was dangerously close to bein wrong, but when he got into back-reactions it seemed to me like he was tryin to clarify hisself.

QUOTE (->
QUOTE
The whole discussion then gets further and further away from the original dispute.  shalayka talks about isolated rotating sources in response to AN's discussion of them,  while AN starts talking about back reaction, so they have essentially swapped topics, adding to the confusion.

That actually cleared up some confusion with me. I was confused, thinkin that AN posted some physics that was dangerously close to bein wrong, but when he got into back-reactions it seemed to me like he was tryin to clarify hisself.

The Kerr solution does have a spherical event horizon, but the metric itself is not globally spherically symmetric.  For instance, the ergosphere is oblate.  Once again, I'm sure AN knows this, but his post reads as if he thinks otherwise.

Right, but it were my understandin that the ergoregion's contribution to a black hole's potential fer producin gravitational waves was negligable, meanin fer the purposes o this discussion the Kerr metric would be functionally spherically symmetric. I can see how I'd be wrong there, but I didn't reckon I was.

QUOTE
A spherically symmetric SUBsystem, which is gravitationally interacting with another body to form a larger system, CAN radiate.

That were the crux o my takin sides here, although in all honesty I'm predisposed to AN's side in any physics debate, based on the fact that I know he knows what he's talkin about. I saw him specifically state that, an jes a few minutes later, I saw Shalayka claim he said the exact opposite.

QUOTE (->
QUOTE
A spherically symmetric SUBsystem, which is gravitationally interacting with another body to form a larger system, CAN radiate.

That were the crux o my takin sides here, although in all honesty I'm predisposed to AN's side in any physics debate, based on the fact that I know he knows what he's talkin about. I saw him specifically state that, an jes a few minutes later, I saw Shalayka claim he said the exact opposite.

An isolated rotating NEARLY axisymmetric system CAN radiate provided it has nonvanishing quadrupole moment due to mass distribution within the object.

Planets radiate due to their orbital motions AND due to their rotations (provided they are not perfectly axisymmetric).

That goes back to what I was sayin bout why I didn't take issue with AN's first statement.

...
All the rest o what ya said don't need my commentary to make my views clear; I agree.
...

QUOTE
If one reads his posts without ASSUMING he is an idiot, then one finds that real communication can take place.

That's the problem. I seen him deny gravitational radiation even exists, not to mention get some basic physics wrong. Th'way I see it, I'm only one step removed from idiocy when it comes to physics, an if I can correct someone... Well, let's jes say I find that a bit tellin...

QUOTE (->
QUOTE
If one reads his posts without ASSUMING he is an idiot, then one finds that real communication can take place.

That's the problem. I seen him deny gravitational radiation even exists, not to mention get some basic physics wrong. Th'way I see it, I'm only one step removed from idiocy when it comes to physics, an if I can correct someone... Well, let's jes say I find that a bit tellin...

...whacking blindfolded at each other with bats, while the great pinata of truth lies all undiscovered before them.

laugh.gif Hell, ya made me groan with that one...
Iori Fujita

The first theory is "The light bends the gravity".
The second theory is "The matter produces the gravity field, and the energy of emission produces the separation field".

---------------------------------------------------------------------------

Let's change the Einstein field equation a bit.

Einstein original Rab - 1/2 * Rgab = 8paiG/c^4 * Tab

Modified version Rab - 1/2 * Rgab = 8paiG/c^4 * (Tmab + i*Teab)

Here: Tmab is the stress tensor by matter
Teab is the energy tensor by emission energy

Then this should be the Modified Einstein Field Equation (MEFE).

It is said by all the people that the gravity has the same intensity regardless of the direction of measurement and that it is isotropic. But I think that the gravity will work not only three dimensionally but also two or one dimensionally. In the two or one dimensional gravity, the gravity will be concentrated in one plane or line and will have a stronger effect than three dimensional gravity has. Then the separation forces are necessary in order to smash the gravity into two or one dimension.
Then the imaginary factor is necessary.

According to the Einstein Theory;
Matter warps the continuum according to the amount (or mass) which exists in any locality. Then all motion along world lines in the vicinity must follow the warp.If world lines must follow warps in space, beams of light passing near the mass should be deflected with a certain angle.
But here for me, the light can't be deflected one-sidedly. It should also affect back the gravity field. Beams of light will loosen the gravity field to the orthogonal direction slightly. And huge amount of beams of light or emissions will shove away the gravity field in a thin-depth disk.

There are three phases of the relation of gravitation and separation.

elliptical galaxy e.g. NGC4881 "Three Dimension" -> ordinary Newton's equation
GM(<r)m/r^2 = mv^2/r
gravitationally unstable

barred spiral galaxy e.g.NGC1300 "One Dimension" -> new New1ton's equation
G''M(<r)m = mv^2/r

spiral galaxy e.g. NGC4414 "Two Dimension" -> new New2ton's equation
G'M(<r)m/r = mv^2/r
gravitationally stable

There are also phase-shifts among those three phases.

---------------------------------------------------------------------------

The Law of Universal Gravitation and Separation

It is the universal force which unifies gravity and separator into one. No one ever knows about the separator force. So now, I give a definition of the law of universal separation at first.

Fs = - Sp Ea Eb / r^2 F ; the separation force
Ea ; Energy which belongs to the point a
Eb ; Energy which belongs to the point b
r ; the distance between a and b
Sp ; the separation constant
This force will not be detected on the Earth. It can be negligible even in the solar system. But it will work in the galactic scale.
Next step is to unify Gravitation and Separation into one law.

Fg = G Ma Mb / r^2 -----------------Then,
Fg+s = G Ma Mb / r^2 - Sp Ea Eb / r^2


And assume that Sp = G / c^4, because E = mc^2.

Fg+s = G Ma Mb / r^2 - (G / c^4) Ea Eb / r^2

One step forward by using the complex number formula.

F = G ( Ma + i Ea / c^2 ) ( Mb + i Eb / c^2 ) / r^2
F = G Ma Mb / r^ - (G / c^4) Ea Eb / r^2 + i ( G Ea Mb / ( r^2 c^2 ) + G Ma Eb / ( r^2 c^2 ))
The real part is Re( F ) = Fg+s, but I don't know how to deal with the imaginary part ; Im( F ) = G Ea Mb / ( r^2 c^2 ) + G Ma Eb / ( r^2 c^2 ).

So an existing substance is to be described as S = M + i E / c^2 .
In a certain independent area, if M + E / c^2 = constant ( in other words when M decreases by ΔM, E will increases by ΔE = ΔM c^2 ), then abs( S ) = will be minimum when M = E / c^2, because abs( S ) = root( M^2 + E^2 / c^4 ).

"Energy" is the emission of light. In the beginning there was only the light with the energy ( = Eo ). At present equilibrium, the total matter in the space is (1/2)Eo/c^2 and the total energy has decreased to (1/2)Eo.


http://www.geocities.jp/imyfujita/galaxy/galaxy01.html
Iori Fujita

philip347
The theory on dark matter, is that it is not just spacing, as you have in the website offered.
It is something else.

There are errors in your conception of creation.

The direction sought after, is man’s direction towards space.

Mankind cannot do this, as his Earthbound politics, so overshadows any possibility of a normal natural meeting with other beings, that the entire nature of the astronautics program is in question.

They keep broadcasting both the future to come and the possibility of world war three.

What they are after, are the doings of the last great races that were here, so that they can say they are free and all debts are paid.

These are the problems with the depth of what you offer, if you are real.

Other notes: If someone knows the outcome of time, then they become a regimental schizoid and psychotic.

If there are superstars based near Earth and Earth chooses to participate in an atomic war, then the quality of those weapons will far outweigh the ones used in very past ancient wars.

There is a very possible chance, that through the products of wormhole conveyance, that both or more superstars could be set off.

Then this area of space would become poisonous as well as worthless.
Iori Fujita

Galaxies are arranged into sheets and filaments surrounding vast empty voids. Galaxies have "two or one dimensional" gravitational spreads which will work as "surface tension" for forming large scale bubble, or void, structures.
Iori Fujita
Iori Fujita
I think that the nameing "MEFE" is good.
Iori Fujita
In the New2ton;
One trajectory of a matter has both the nearest and the furthest point from the center of the galaxy. And the circle tangent velocity against the center of the galaxy is to be constant. Then where has been the potential energy? We can find it in the vertical movement. When the trajectory comes the nearer to the center of the galaxy, it will sway up and down the more rapidly.
Iori Fujita

Dr Fred A Wolf
QUOTE (Iori Fujita+Jun 20 2008, 01:32 PM)
I think that the nameing "MEFE" is good.

.... only if it's a acronym for Mindless Excrement For Eejits. smile.gif
Iori Fujita
Genesis 1:3 And God said, Let there be light: and there was light.
Genesis 1:4 And God saw the light, that [it was] good: and God divided the light from the darkness.
Iori Fujita
Iori Fujita
The simpler , the better!
There are New1ton's, New2ton's and Newton( or New3ton)'s equations.
And I have the Einstein Field Equation EFE and the Modified Einstein Field Equation MEFE.
Then I don't need Dark Things like dark matter or dark energy.

Iori Fujita

http://www.geocities.jp/imyfujita/galaxy/galaxy01.html
AlphaNumeric
QUOTE (Iori Fujita+Jun 23 2008, 11:12 PM)
The simpler , the better!

Except when it's wrong. For instance, the simplest model is "Gravity doesn't exist". But it's wrong.
QUOTE (Iori Fujita+Jun 23 2008, 11:12 PM)
And I have the Einstein Field Equation EFE and the Modified Einstein Field Equation MEFE.
Except they don't work.

They don't predict physical things. They are something you just pull from nowhere. They are a demonstration you don't know anything about relativity.

Please answer the following questions directly :

1. Can you derive your modified equations from base postulates?
2. Can you derive physical predictions, such as the equations of motion, for phenomenologically important systems from your equations of motion?
3. Do you understand a complex manifold is, compared to a real manifold?
4. Do you understand that general relativity is based upon a real manifold?
5. Do you understand that this means that except when you're Euclideanising the metric, there should be no factors of 'i' in any equation?
6. Do you understand what 'Equating real and imaginary parts' means in basic complex algebra?
7. Do you understand that in your 'modified equations' the left hand side is real and therefore the imaginary part of the right hand side must be zero.
8. Where did you learn general relativity and differential geometry? A university? A book? A correspondence course? Nowhere?

Failure to answer this direct questions which be seen as an admission you are either unable or unwilling to answer them. If you've nothing to hide, you should be able to answer them easily.
Iori Fujita
An existing substance is to be described as S = M + i E / c^2 .
In a certain independent area, if M + E / c^2 = constant ( in other words when M decreases by ΔM, E will increases by ΔE = ΔM c^2 ), then abs( S ) = will be minimum when M = E / c^2, because abs( S ) = root( M^2 + E^2 / c^4 ).
Iori Fujita
Iori Fujita
The space-time interval is written as;
ds^2 = dx^2 + dy^2 + dz^2 - c^2 dt^2

Then I rewrote it to;
ds^2 = dx^2 + dy^2 + dz^2 + (ic)^2 dt^2

The momentum p, E = (m^2 c^4 + p^2 c^2)^(1/2).
I rewrote it to;
E = abs(m c^2 + i p c)

Iori Fujita


Iori Fujita

Prof. Hawking said that it is possible for a space-time with the imaginary time to be finite in extent and have no singularities that formed a boundary or edge. But he didn't mention the separation force created by Light with the existing the imaginary energy tensor by emission energy.
Iori Fujita

Iori Fujita

The imaginary part is said to be rather controversial in the community of theoretical physicists. Some say that it is merely a convenient tool without any physical significance. The imaginary and real can be only just mathematical terminologies. It has nothing to do with what you see or want to see.
Iori Fujita

AlphaNumeric
QUOTE (Iori Fujita+Jun 26 2008, 10:36 PM)
The space-time interval is written as;
ds^2 = dx^2 + dy^2 + dz^2 - c^2 dt^2

Then I rewrote it to;
ds^2 = dx^2 + dy^2 + dz^2 + (ic)^2 dt^2

The momentum p, E = (m^2 c^4 + p^2 c^2)^(1/2).
I rewrote it to;
E = abs(m c^2 + i p c)

No. That isn't right. If t->-it then E^2 = m^2 + p^2 goes to :

-E^2 = m^2 + p^2

Yet more proof you don't know how to deal with this in relativity.
QUOTE (Iori Fujita+Jun 26 2008, 10:36 PM)
The imaginary part is said to be rather controversial in the community of theoretical physicists. Some say that it is merely a convenient tool without any physical significance. The imaginary and real can be only just mathematical terminologies. It has nothing to do with what you see or want to see.
But that isn't in reference to your work Your work is wrong.

Iori, why are you ignoring my questions? Got something to hide?
Iori Fujita

How do you explain galactic rotation curves without dark matter?

This was the a point of departure for me to imagine the cosmos cultivated without chemical fertilizer like dark matter. Dark matter is fabricated for the explanation of galactic rotation curves (but later days, dark matter wants to be on its own and is positively ubiquitous.). The galaxies are now suffered from metabolic syndrome with high blood pressure, central obesity (also known as visceral, male-pattern or apple-shaped adiposity), overweight with fat deposits mainly around the waist, decreased HDL cholesterol and elevated triglycerides. They actually don't know their own weights.
Iori Fujita

AlphaNumeric
Well done at ignoring everything I asked you.
Iori Fujita
MEFE is a good name. But MOND is better only for the naming. Mond means world.
Iori Fujita
Iori Fujita
But MOND means nothing but meaningless ajustment. It said that when r is somehow great, 1/r becomes more.
Iori Fujita

Iori Fujita
MEFE is different from MOND. It is consistent with the basic philosophy.
Iori Fujita
AlphaNumeric
Iori, why are you ignoring my questions? Got something to hide?
Iori Fujita
I read "Dark Cosmos by Dan Hooper". It said "This invisible stuff comes in two varieties—dark matter and dark energy. One holds the Universe together, while the other tears it apart."
Iori Fujita

Iori Fujita