Although I would think the pump should have shut off if there was no way for the air to escape and you were just compressing it.
QUOTE
...that batteries lasted longer if they were stored in a cold place.
You don't gain much for your effort.
QUOTE (->
| QUOTE |
| ...that batteries lasted longer if they were stored in a cold place. |
You don't gain much for your effort.
Battery life can be extended by storing the batteries at a low temperature, as in a refrigerator or freezer, because the chemical reactions in the batteries are slower. Such storage can extend the life of alkaline batteries by ~5%; while the charge of rechargeable batteries can be extended from a few days up to several months. In order to reach their maximum voltage, batteries must be returned to room temperature; therefore, alkaline battery manufacturers like Duracell do not recommend refrigerating or freezing batteries.
newguy
28th May 2008 - 11:20 PM
xtrmn8r: Thanks for the battery info. I went to the link and also saw this:
Life of primary batteries
Even if never taken out of the original package, disposable (or "primary") batteries can lose 8 to 20 percent of their original charge every year at a temperature of about 20°–30°C.[65] This is known as the "self discharge" rate and is due to non-current-producing "side" chemical reactions, which occur within the cell even if no load is applied to it. The rate of the side reactions is reduced if the batteries are stored at low temperature, although some batteries can be damaged by freezing. High or low temperatures may reduce battery performance. This will affect the initial voltage of the battery. For an AA alkaline battery this initial voltage is approximately normally distributed around 1.6 volts.
It seems that colder temperatures can have either a "positive" or "negative" effect on batteries...no pun intended. Anyhow, thanks again for the input.
Precursor562
29th May 2008 - 01:32 AM
Back to the original question.
Shaking a bottle of pop (as stated) will not increase the pressure within the bottle. When shaken the liquid will place small bubbles of compressed gas into the liquid (which upon unsealing, these bubbles expand causing the eruption) but this doesn't take away from the pressure in any way since the whole thing is a sealed unit and the small bubbles are of compressed gas each exerting a small pressure within the . So even if the gas was taken from the pocket above the liquid, it is merely relocated within the confinement.
mr_homm
29th May 2008 - 02:54 AM
I'm not sure I believe that there is NO pressure increase when you shake up a soda drink. For instance, from personal experience, you can squeeze a plastic bottle of soda which has been sitting still for a while, shake it, and squeeze it again, and you can FEEL that it is firmer. My guess here is that the plastic bottles are not altogether impervious to vapor, and so the vapor in the gas phase diffuses out slowly, which leaves the pressure in the bottle at atmospheric pressure, or close to it. Meanwhile, the dissolved gas in the liquid phase becomes supersaturated because its vapor pressure is now higher than the pressure in the bottle, but it does not immediately change phase. This would be similar to supercooled water not immediately forming ice. The contents of the bottle would attain a metastable state, in which a disturbance (such as shaking) would cause the dissolved gas to evaporate and restor equilibrium.
The explanation (that soon after shaking, there are many small bubbles floating in the liquid, which rapidly expand when the bottle is opened, and carry a jet of liquid out with them) sounds like a good reason for the FOAM, doesn't really address the pressure change. In other words, I think that the presure increase is real (though small) but is unrelated to the jetting effect. A further personal experience is that you can measure the liquid level in a plastic soda bottle before and after shaking, and you will find that it is slightly lower after shaking. This indicates to me that the bottle has expanded slightly, which is an objective indication of higher pressure. Of course, it may be true that for CANS, the permeability is so low that the gas does not diffuse out, so my explanation may only apply to plastic bottles.
As to the gasoline tank question, since I don't know the internal configuration of the gasoline tank, this is just a guess: Suppose that some (very foolish) engineer decided that the tank needed a tube leading from the external opening down to near the bottom of the tank. (I can't think of a single reason why anyone would do this, but it would produce a nice gasoline jet, so perhaps this is the way the tank was made.) In order to fill the tank at all with this arrangement, you would need some kind of vent at the top, since the tank would tend to trap air, so suppose there was such a vent (another bad idea) and that it was clogged. Then all the trapped air in the tank would pressurize when you tried to fill it, and when you removed the nozzle, the pressure would expel pure liquid gasoline straight up the fill spout. With a tank like this, a pressure P will, when released, produce a jet that rises to a height given by P = dgh, where d is the density of gasoline. Therefore, h = P/dg. Since d = about 700kg/m^3 and g is roughly 10N/kg, this gives h = P/(7000N/m^3). Even a pressure of 0.1atmoshere = 10000N/m^2 would shoot gasoline to a height of about 1.4m. This is certainly high enough to get all over the entire car and the person pumping the gas. While this would explain the geyser, I can't believe that anyone would really design a tank like that.
--Stuart Anderson
xtrmn8r
29th May 2008 - 03:29 AM
mr_ homm,
QUOTE
While this would explain the geyser, I can't believe that anyone would really design a tank like that.
I would if it were an British made car
buttershug
29th May 2008 - 11:14 AM
Liquids disolve gasses.
Sodapop has disolved Co2. Disolved CO2 does not add to the pressure.
You shake the can or bottle and it makes the CO2 come out of the solution.
It now adds to the pressure since it is not longer disolved.
Slamming the can down on a hard surface will be more effective. I've seen cans pop open whne that was done to them.
And remember solubilty of a gas in liquid is inverse to the temperature.
Bloy
29th May 2008 - 12:54 PM
..just my thoughts...
Filling a gas tank creates turbulence. Some pumps inject the petrol at higher velocities. As the liquid is filling the tank, petrol and air are sloshing about. Like a boat can lose buoyancy and sink, the sensor that shuts off the pump is no longer responsive due this air/petrol mixture and thus allows the tank to rise to a level where the "aerated" petro is literally blown out the inlet as the delayed shutoff mechanism miscalculates the actual petrol level in the tank. This occurs too when "topping off" a tank....the petrol is already up to the filling tube and a momentary injection of the petrol will cause a "blowout" before the sensor can again shut off the supply.
Understanding that this happened many years ago, I think the interpretation of what actually happened may have been slightly distorted, or mis-remembered.
buttershug
29th May 2008 - 01:06 PM
As far as I know the sensor is simply a pressure detector, not any kind of level detector.
Bloy
29th May 2008 - 01:39 PM
QUOTE (buttershug+May 29 2008, 07:06 AM)
As far as I know the sensor is simply a pressure detector, not any kind of level detector.
right... the vacuum that is increased to shut off the pump does not materialize (in time) because of the aerated fuel and thus overfills.
...and since the filler tube was probably longer than usual, being on top of the trunk, the aerated fuel went shooting up the tube and out while the sensor was still looking for an increase of vacuum.
buttershug
29th May 2008 - 03:06 PM
QUOTE (Bloy+May 29 2008, 01:39 PM)
right... the vacuum that is increased to shut off the pump does not materialize (in time) because of the aerated fuel and thus overfills.
...and since the filler tube was probably longer than usual, being on top of the trunk, the aerated fuel went shooting up the tube and out while the sensor was still looking for an increase of vacuum.
Increase of vaccuum?
I was thinking of positive pressure.
We have a selective solder machine at work. The way it detects the solder level is by using the pressurized nitrogen. When the solder is at the proper level it blocks the level dection nozzle which means the nitrogen is at full pressure. When the solder level drops the nitrogen can escape and thereby lowers the pressure and sets off the low level detection.
I was imagineing something similar with gas pumps, when the nozzle is clear there is little back pressure. When the nozzle is blocked by a full tank there is more back pressure and the pump shuts off.
gmilam
29th May 2008 - 03:12 PM
How does a gas pump shut off automatically when the gas tank is full?And he said this was 30 years ago... we were a lot more primitive back then. Gas was still under a dollar a gallon!
Bloy
29th May 2008 - 03:34 PM
...a cross section view of the sensing mechanism of a gas pump nozzle:
http://www.wonderquest.com/figure-gas-nozzle.htmI wouldn't say there aren't many other designs for shutting off fuel flow....this is just a "typical" fuel nozzle.
buttershug
29th May 2008 - 03:58 PM
QUOTE (Bloy+May 29 2008, 03:34 PM)
...a cross section view of the sensing mechanism of a gas pump nozzle:
http://www.wonderquest.com/figure-gas-nozzle.htmI wouldn't say there aren't many other designs for shutting off fuel flow....this is just a "typical" fuel nozzle.
Next time I fill up I will have to look for that hole.
Does anyone know if I"m also out to lunch with my theory that shaking the pop causes CO2 to come out of solution?
I mean the more CO2 you have that is not dissolved the higher the pressure in a closed container.
Bloy
29th May 2008 - 05:43 PM
QUOTE (buttershug+May 29 2008, 09:58 AM)
Does anyone know if I"m also out to lunch with my theory that shaking the pop causes CO2 to come out of solution?
I mean the more CO2 you have that is not dissolved the higher the pressure in a closed container.
I would say you are NOT out to lunch.....just a hunch..
When you shake the container, after it has been sitting for a while, the pressure will increase as more surface area of the liquid is exposed. The agitation facilitates exchange of CO2 into a gaseous state. When again at rest the CO2 will naturally reabsorb into the solution lessening the pressure until some equilibrium is reached.
Don't take my word for it though!

mr_ homm mentioned this in his post a while back...
newguy
30th May 2008 - 11:15 AM
All: Once again, I thank everybody for their contributions in attempting to answer my question. I found this website a few moments ago...I think this might effectively answer my question. Any future comments are welcome. Thanks.
http://www.jagbits.com/29whooshing.html29. "Whooshing" Fuel Tanks in Series III XJ6 Jaguars
Jaguar Parts Technical Information
The Series III XJ6 Jaguar has a fuel vapor recovery system, which captures excess fuel vapors inside the charcoal canister located in the front right fender. Sometimes this system gets clogged or a pressure valve malfunctions, leading to a substantial vacuum in the fuel tank. The most noticeable symptom is a whooshing sound when you open the fuel tank filler caps. This whooshing sound is bad news. The vacuum builds up in the tank until the sides of the tank suck in a little. Then, when the filler caps are opened, the fuel tank expands back out. You can sometimes hear the tank popping back into shape. Do this a lot and the tank will crack from the flexing and start to leak. The usual suspect is a little valve right next to the charcoal canister, inline with a rubber hose leading to the canister. When that valve fails, the vacuum builds up. The only fix for this is to replace the valve. Fortunately, this "pressure valve", part number CAC3101 is pretty inexpensive at around $30. Ok, for a cheap little plastic part that's pretty darn expensive, but it's certainly cheaper than $470 for a new tank!
Precursor562
30th May 2008 - 04:44 PM
Just a though for the CO2. The liquid can only dissolve so much gas. This depends on the pressure that is applied to the liquid. The higher the pressure, the more gas that can be dissolved into it. Although there is no doubt an ultimate limit there.
So if the bubbles formed are the dissolved gas then there still shouldn't be an increase in pressure because an increase in gaseous bubbles is a direct result of a decrease in dissolved gas. If the amount of gas dissolved is a result of being under pressure then it should apply an equal and opposite pressure back. Since it is compressed gas that is applying the pressure if the pressure being applied back (equal and opposite and what not) is not equal then one of two things should happen.
1. The pressure being applied by the external gas is greater and will become dissolved into the fluid until an equilibrium is obtained.
2. The pressure being applied back by the dissolved gas is greater and will form bubbles which will eventually make their way to the surface adding to the external gas. Again forming an equilibrium.
Again, just a thought.
buttershug
30th May 2008 - 05:08 PM
So light needs to accelerate to get up to speed but gas dissolves instantly?
And your number 2 doesn't make sense.
It doesn't matter where the bubbles are. They can be spread throughout the pop or at the top. And I don't believe the dissolved gas adds any pressure, it's only when it comes out of solution to form bubbles that it contributes to the pressure.
I want to make sure I understand you.
Are you thinking that the bubbles are the dissolved gas?
Because they are not. The dissolved gass is, well dissolved, it's part of the liquid.
If it's in a bubble it's not dissolved in the liquid.
Get a glass of water. There is dissolved CO2 in it.
We make DI water for our wash machine. As it is made it has a PH of 7. I havn't checked but have been told that it quickly goes down minutely because it dissolves CO2 out of the air.
Get some cold water out of your tap. Put in ice cube trays. Put it in the freezer, you will see when it freezes that it is cloudy. This is air undisolveing as the water freezes. But you didn't see bubbles before you froze it did you?
buttershug
30th May 2008 - 09:49 PM
QUOTE (mr_homm+May 29 2008, 02:54 AM)
Of course, it may be true that for CANS, the permeability is so low that the gas does not diffuse out, so my explanation may only apply to plastic bottles.
--Stuart Anderson
Once I saw a can of pop slammed on a table instead of being shaken. The can then burst open. To me this would indicate that the pressure did indeed go up do to the mechanical shock.
another time I was driving with some cans in the back of the car. I went over a bump and heard a noise. then I noticed my car top was dripping. Later I found a can that had burst open. Now it may have been strictly because of the can getting warmer but I doubt it.
Precursor562
30th May 2008 - 10:22 PM
QUOTE
And your number 2 doesn't make sense.
See this. This is called arguing for the sake of arguing. Not because of the info, but because of the person.
Take a new bottle of pop (soda). Look inside and you will see very few bubbles (if any). Crack open the bottle and you will see bubble appear withing the pop. Open it until there is no his and you will see bubbles form and rise to the surface. Close the bottle. Over time the bubbles that form and rise will build up a pressure and more bubbles will stop forming when an equilibrium is obtained.
QUOTE (->
| QUOTE |
And your number 2 doesn't make sense.
|
See this. This is called arguing for the sake of arguing. Not because of the info, but because of the person.
Take a new bottle of pop (soda). Look inside and you will see very few bubbles (if any). Crack open the bottle and you will see bubble appear withing the pop. Open it until there is no his and you will see bubbles form and rise to the surface. Close the bottle. Over time the bubbles that form and rise will build up a pressure and more bubbles will stop forming when an equilibrium is obtained.
So light needs to accelerate to get up to speed but gas dissolves instantly?
Where was the use of the word "instantly"? I believe I said "eventually" at one point which implies a passing of time.
QUOTE
Are you thinking that the bubbles are the dissolved gas?
The bubbles were once dissolved gas. That is what I meant. An increase in bubble results in a decrease in dissolved gas provided that the gas that comprises the bubble once was the dissolved gas.
Bad wording on my part. Sorry.
QUOTE (->
| QUOTE |
| Are you thinking that the bubbles are the dissolved gas? |
The bubbles were once dissolved gas. That is what I meant. An increase in bubble results in a decrease in dissolved gas provided that the gas that comprises the bubble once was the dissolved gas.
Bad wording on my part. Sorry.
Get a glass of water. There is dissolved CO2 in it.
There is also atmospheric pressure being applied onto it. We have a machine for testing the contamination of hydraulic oil taken from aircrafts. Before the machine can be used on the oil, the oil must first be put into a chamber where it undergoes a decrease in atmospheric pressure. This forces dissolved gas (that can interfere with the testing) to form bubbles and rise to the surface.
Enthalpy
31st May 2008 - 01:36 PM
Wow! This topic seems to attract the imagination of many people. Thanks to all of you!
I too consider that the pressure in the bottle increases, and not just by a few millibars, because I too feel the brutal tension in the walls of a plastic bottle when the beverage has been shaken. As a comparison, the stiffening of the bottle by your lung's pressure, which is about a quarter atmosphere, is much weaker.
The dissolved CO2 is in equilibrium with the gaseous CO2 over the liquid, which is a bit over atmospheric pressure when the bottle is filled and stored. But why should the pressure increase when shaken? Neither the temperature nor the chemical composition is changed.
A long quiet storage doesn't increase the pressure neither, so I don't believe shaking simply accelerates some degassing.
Confused2
31st May 2008 - 10:45 PM
The C2 explanation is that shaking a fizzy drinl bottle produces very small bubbles with very high pressure due to surface tension .. the bubbles subsequently coalesce into larger bubbles .. the rest is hydraulics. A bottle containing just air and water does not contain enough excess gas to produce the effect .. the C2 effect predicts shaking will (slightly) reduce the internal pressure of a bottle containing just air and water in equilibrium.
Confused2
1st June 2008 - 07:10 AM
Hi 5D,
Let's do this in easy steps..
If you look at the page here
http://en.wikipedia.org/wiki/Interfacial_tension (click on the link) you'll see that inside a 1um bubble there is an excess pressure of 1.46 atmospheres. If we start with (say) 10cm^3 of air and shake it up in water so it all ends up in (say) 1um bubbles .. what volume will it occupy? Will it be MORE or LESS than 10cm^3 ?
-C2.
Confused2
1st June 2008 - 07:26 AM
Hi 5D,
Saturated solutions are an advanced topic which we won't attempt until we've established we know the relationship between pressure and volume .. (try to remember that this is physics for bozos .. we have to take small steps)
Just try the question again .. eventually you might see why I'm asking it.
-C2.
Confused2
1st June 2008 - 08:12 AM
QUOTE (5D+)
In addition, headspace pressure in typical Cola bottles is around twice atomospheric pressure. - see where I going with this ?
I think you are heading in the direction of being able to explain to the nurse why you are covered in a sticky brown liquid - whether or not she will believe you is another matter.
-C2.
Confused2
1st June 2008 - 09:51 AM
Out of respect for the decent folk posting on this thread/forum I have reported the last two posts and asked for them to be removed .. I hope others will do the same. Thank you. -C2.
Precursor562
1st June 2008 - 02:15 PM
Just curious of something said earlier. Does dissolved gas really not exert any pressure? That is given a bottle of pop, does the dissolved gas not contribute to the pressure found within the bottle?
The reason being because of the existence of TGP probes.
TGP = Total dissolved Gas Pressure.
Enthalpy
4th June 2008 - 03:16 PM
May I remind that disregarding words are not considered as convincing arguments in a scientific discussion?
Edward 3
4th June 2008 - 03:56 PM
C2,
You´re feeding them again !! This could lead to an even faster rate of reproduction !!
all the best
E3
Enthalpy
4th June 2008 - 03:58 PM
Tiny bubbles are an interesting direction.
I had read a long time ago, but have largely forgotten, that the gas <-> solution equilibrium is displaced when bubbles (or droplets) are small. Could it be a simple geometrical effect, because the strong curvature means that gas molecules located, say, one mean free path over the solution, are less abundant since the smaller sphere there has less area?
Then more CO2 would evaporate to a tiny bubble than it would at a flat surface.
But maybe my memory is simply too bad.
Oversaturated solution: no. As I already wrote, a long storage doesn't have this effect, even in a metal can upside down, which has visibly no leak.
Sugar: no. I saw the effect on Coca light, which contains none. It is, in fact, water with CO2 and very little more. Carbohydrates are under 1g per 100g liquid. All aromas, vegetal extracts, caramel colour that make the difference with tap water and industrial CO2 are together well under 1%.
Pressure from the dissolved gas: how to tell? As soon as the free gas in the bottle has a pressure, the liquid or solution transmits this pressure. It could be hydraulic oil or liquid Ga-In-Sn alloy (Galinstan), with no CO2 dissolved, and these liquids would transmit the free gas' pressure.
What is sure is that the pressure of the free gas increases (as much as the liquid's pressure) and for that, some gas must escape from the solution.
Enthalpy
4th June 2008 - 04:30 PM
And eventually I looked at the Wiki page linked by Confused2:
http://en.wikipedia.org/wiki/Interfacial_tensionwhich tells much useful information relevant to the discussion.
- Sugar has no effect on water's surface tension
- Vapour pressure of tiny droplets is bigger than for a flat surface (see just above the pictures gallery). Maybe the free gas pressure of a solution does the same.
Enthalpy
5th June 2008 - 03:53 PM
Sec, you should choose better data sources.
Handbook of Chemistry and Physics:
The surface tension of water changes only from 72 to 75.7 mN/m when increasing the diluted sucrose from 0% to 50% weight. In other words: no significant effect.
Confused2 has brought useful inputs in this discussion. You have only brought false data, false ideas and disregard.
You can't make science from data picked at answers.yahoo.
You can't make science from insults.
You can't make science at all.
barakn
5th June 2008 - 06:21 PM
Thought I'd add my two cents. Shaking the cola adds mechanical energy to it, and since shaking is quite a turbulent process that mechanical energy quickly becomes heat. This heat will increase the temperature of the liquid and gas phases, decreasing the solubility of the CO2 and increasing the pressure of the gas. The pressure should increase even if there is no degassing of the liquid.
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