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21st November 2006 - 10:34 PM
Im trying to figure out this problem, but Im not sure if I have the equation(s) I need.
"A ball is thrown horizontally out the window of a building with a velocity of 8.0 m/s from a height of 2500 m. How far from the base of the building will the ball land?"
a) 54 m
B) 60 m
c) 90 m
d) 115 m
e) 180 m
The equations I have for the X value (distance in X) include the following:
Vx = ▲x/▲t
▲X = V0 * ▲t
Vfx^2 = Vix^2
Is this all I need to find the answer? Or am I missing some equation(s)?
21st November 2006 - 10:50 PM
This is pretty simple. You need to use the free fall equation too. First find the time it takes the ball to fall the 2500 meters. When you have reached this time, the ball will be the furthest from the building. So find the time it takes for the free fall portion, then use that time and solve for the distance away from the building.
free fall: y=yintial+Vyinitial-1/2gt^2
yintial and Vyinitial are 0
solve for time
Distance away from building=velocity*time
21st November 2006 - 11:13 PM
thanks for the help. I figured the time out as 22.6seconds, and the answer to 180.8, which is close enough to answer choice E. Thanks blackhar
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