phi(x)=(V/d)x (phi:electric potential, x:distance, V:voltage between capasitor plates and d: distance between plates)
when i know the electric field is homogeneous: phi(x)=Ex + b
Should be easy to solve
17th January 2012 - 04:15 PM
I'm not sure I'm getting this, but isn't the potential phi the integral of the field E from x=0 to x=d?
\nabla phi = -E => phi = - \int_0^d E dx = -Ed ==> E = -phi/d
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