ok, hopefully this makes sense. Rotation is also called a moment. Moment equals force*(distance from center of gravity). For a slender rod, aka stick, the center of gravity, assuming mass is distributed equally should be the center of the stick...so if you have a 4m stick the center of gravity should be 2 meters from any end. I guess the main thing you would have to figure out is how much force is applied. So if the force is applied at the center of gravity no rotation, or moment, should occur. Hope that makes sense.
Thanks oomchu,
But im not clear on how you would explain a mouses force on the stick. Also what would need to be done if user applies mouse force at a 45' angle from the stick... like
=========C========= <<< stick
------------------------------*
----------------------------*
--------------------------*
------------------------*
----------------------*
--------------------*
------------------*
----------------*
---------------^ force applied at a angle
C being the center of gravity..
and the "*" represents the angle of the force.
Thank you,
Najam D.
Agwan
12th June 2006 - 07:48 AM
If a force "N" is applied at an angle of lets say "theta" degrees starting from straight right, then the force applied on the stick at a lenght "l" from the center point is calculated:
force applied on stick around its axis of momentum = N*sin(theta)*l
This is the force that will make the stick turn.
theta can also be seen as the angle between the stick and the force. If you wanna know the force applied on the stick in its line it is:
force applied along stick = N*cos(theta)
This force will cause the stick to move unless it is stuck at its center of momentum.