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elissa
Ok this is not a homework and im not even a student anymore BUT my boyfriend is an engeneer and the other day he told me that i could never understand what he is doing...and of course being a woman i kept telling him i could sad.gif even though i cant BUT i soooo want to show him that i can do it (ok i wont be the one doing it) but plsssssss
he'll be so impress laugh.gif

but he wont know i didnt do it ph34r.gif

so heres the thing:

I have a diffuser with water flowing within at 300c and .05Mp, 100m/s as velocity and 0.1m˛ as area. All at the inlet of the diffuser.
WHile flowing through the diffuser there was a heat transferred from the system to the sorroundings, considering this is a steady state steady flow system, find me the temperature of the system and the area at the outlet of the diffuser.

huh.gif blink.gif this is like talking chinese to me

anyone pls?
philip347
The problem is ,variable as the water outlet, acts as a coolant.Note, you did not state a water temperature,, is this to be understood as ambient?

You need the exact temperature and the size and dimensions of the water diffuser.

*The air outside of the water diffuser outlet area, would have a tendency to be non stable at first, then depending on flow rates, either set into an approximate range, or a varied flux rate temperature, as the action of diffused water acts similar to a shock absorber.

The ambient air flow around the bottom of Niagara Falls, is always variant, as your dealing with tons of water, flowing over a localized area.

However the action of a stand of air, is fluxual, primarily because the action of the water over the falls, is a segmented per-length phenomenon.

So the conditions below the falls within a localized area, are never the same, as the down-flow from the falls, acts as a hydraulic stimulator, to both air pressure and air pressure action within that confined space.

So this might be a trig formula, to where measured outflow, represent an action (where ) to the surrounding area, mixed with the know differences in ambient air cooling.

Thank you for your question, Phil for phys.org
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