The question is: To what temperature must a 500g brass weight be heated to just convert 60g of ice at -20C to water at 20C.
I'm getting it wrong.
MC(delta)T = MC(delta)T + ML + MC(delta)T
heat lost by brass = heat gain by ice, energy to change state, heat gain by water.
im not even sure if this is right. The specific heat of brass is not given on the sheet, but im sure you need it, so in my physics book it says that its 370 J kg K.
0.5 * 370 * (T - 20) = (.06 * 4200 * 20) + (.06 * 3.35*10^5) + (.06 * 4200 * 20)
T = 183 C
the answer is 476C.
So obviously i went horribly wrong somewhere.
Any help telling me how to do this one would be appreciated.
