light in the tunnel
20th September 2009 - 04:40 PM
QUOTE (flyingbuttressman+Sep 20 2009, 02:46 PM)
Fusion does not take place in neutron stars or black holes. In case you were not able to infer the makeup of a neutron star by the name NEUTRON STAR, I will explain it to you.
An atom contains 3 different possible parts. Protons, Neutrons and Electrons. I hope you know their respective charges by now. In a neutron star, the gravitational force is so great that the electrons no longer orbit the nucleus, but are instead merged with the protons to form more neutrons. In the basic sense, a neutron star contains little to no protons or electrons. As such, the neutron star is the equivalent of a giant atom with no electron cloud and no protons.
As for the formation of these two strange stellar bodies, have you not heard of the term supernova? Look it up. All the energy you could ask for is right there.
This is good how?
I already understood this to some degree but your explanation is clarifying it for me. I take it that the charges of protons and electrons are due to some inherent magnetism in them, and that the attraction of electrons to protons is what causes them to orbit and form atoms. Likewise, it is the momentum of the orbiting electrons that constitute the energy of atomic mass. So reconfiguring the atoms into bigger or smaller atoms changes the relationship between the particles and releases energy that is no longer balanced between the electrons and nucleus. So, I guess progressive fusion reactions eject protons and electrons until only neutrons are left, and these neutrons do not orbit each other because they don't magnetically repel or attract each other? So they are able to bunch together very densely, with only the force of their own gravity holding them together and no energy, electromagnetic or kinetic, to cause any dynamism among them?
So then my question is whether independent neutrons ever recombine with protons and electrons to form new atoms? Surely their must be some reaction that would cause this to happen. Let's say, for example, that a massive cluster of neutrons attracts a cluster of stable atoms with its gravity. If the gravity was strong enough, wouldn't it cause those atoms to fuse? And if such fusion occurred, wouldn't the temerature of the neutrons increase? And then wouldn't the heat radiate out into space? - although I don't understand how heat can radiate through space without a medium - I guess supposedly electromagnetic radiation can travel through a total vacuum but I don't see how.
In any case, if a black hole prevents any energy or matter from escaping, then what happens to the energy of the protons and electrons fusing together? The temperature of the neutron cluster must increase in temperature, and would have to move somewhere as a result. I suppose the neutrons could just gain more velocity, and become like a liquid, but then wouldn't they also have to start "boiling" at some point into a gas?
What do neutron clumps do with energy?
flyingbuttressman
20th September 2009 - 04:54 PM
light in the tunnel,
Every time I try to explain something to you, you take it and run in the completely wrong direction. I'm not even going to try to explain what is wrong with what you just wrote. LOOK IT UP! It's really not that hard.
Quantum_Conundrum
20th September 2009 - 11:54 PM
I don't trust the relativistic equations at all as you approach limits.
The reason for this is quantum theory.
Relativity demands continuity. Quantum Theory demands discreet packets, and thus results in a step function for all things.
So, in Relativity, mass supposedly approaches infinity as the velocity approaches the speed of light. The problem is, this function only diverges to infinity if continuity exists.
If discreet packets exist, then there is no divergence, since we cannot take an "arbitrary" number between V and C. This means that velocity can increase from C-Q to C, where Q is the quantum unit of velocity, without an infinite cost in energy.
Again, in the "real world" velocity MUST be a step function since all energy comes in packets of only certain sizes.
Since Q is a discreet packet of velocity, there must be a corresponding discreet packet of energy needed to accelerate by that amount. This discreet packet cannot be infinite in size, since Q is not infinite in size, and is in fact very tiny.
Quantum_Conundrum
21st September 2009 - 02:04 AM
It would be virtually impossible to detect the above difference in a particle accelerator for several reasons.
in order to notice this difference, you would need a measuring device that is accurate and precise to within planck length and time. Even then, you'd have roughly a 50% chance of making an error in measurement that would be large enough to make the result of the experiment useless.
rpenner
21st September 2009 - 02:57 AM
The problem with a quantum of velocity, as I see it, is that the Lorentz transform doesn't transform a regularly-spaced spread in velocities into a regularly-spaced spread in velocities.
Where V is the purported quantum of velocity, 0,V,2V,3V does not look regularly spaced if transformed by c-5V.
And that is just one of the ways the idea is inconsistent with measured Lorentz invariance.