Sithdarth
29th June 2011 - 04:18 AM
QUOTE
On the other hand, our sun emits light across a broad range of spectrums, with no prominent spikes in particular spectrums. (Solar Spectrum) This is known as black body radiation.
1) The sun emits light across a broad range of wavelengths. A broad range of spectra (not spectrums) makes absolutely no sense.
2) Black body radiation a bit more complex than just this.
3)
The solar spectrum is actually an absorption spectrum superimposed on a black body spectrum.
QUOTE (->
| QUOTE |
| On the other hand, our sun emits light across a broad range of spectrums, with no prominent spikes in particular spectrums. (Solar Spectrum) This is known as black body radiation. |
1) The sun emits light across a broad range of wavelengths. A broad range of spectra (not spectrums) makes absolutely no sense.
2) Black body radiation a bit more complex than just this.
3)
The solar spectrum is actually an absorption spectrum superimposed on a black body spectrum.
We use Emission Spectroscopy to determine the composition of interstellar bodies such as stars and nebulae. This works because certain elements only emit light at certain frequencies.
We use Absorption Spectroscopy mainly to get compositions of stars and those nebulae which are lit from within by stars. We use emission Spectroscopy mainly for nebulae which are ionized due to nearby stars but aren't directly lit by a star. Sometimes you can use both on the same nebula depending on the stage of its life. You'll get light from a star passing through some parts and ionizing other parts.
QUOTE
What is the difference between the light produced by a hot interstellar gas and the light produced by our sun? Is the light from our sun a broad range of elements producing different frequencies or am I misunderstanding the conditions for distinct emission bands?
The sun is so hot that the black body spectrum overpowers any emission due to a specific transition. Instead the transitions tend to remove some of the intensity of the black body spectrum giving us an absorption spectrum via which we can get the chemical composition. Generally speaking if the gas is ionized the only light emits is the characteristic transitions due to relaxations. Also, stars are opaque and surrounded by a lot of gas that doesn't emit light. All the light emission of a star happens within a shell of gas that only absorbs light and doesn't directly emit it. In contrast those nebulae hot enough to be ionized produce light all the edge and they tend to be very dispersed. The dispersion means the atoms are more likely to ionize than emit black body radiation. It is also important to remember that inside say the sun were the light is produced the density is so high it is pretty much like a solid and as such the energy levels tend to be more continuous than the discrete energy levels we see in the rarefied nebulae.
What you use is mainly a function of what you are looking at, where you are looking at it from, and what happened to the light between emission and you.
flyingbuttressman
29th June 2011 - 11:21 AM
QUOTE (Sithdarth+Jun 29 2011, 12:18 AM)
The sun is so hot that the black body spectrum overpowers any emission due to a specific transition. Instead the transitions tend to remove some of the intensity of the black body spectrum giving us an absorption spectrum via which we can get the chemical composition. Generally speaking if the gas is ionized the only light emits is the characteristic transitions due to relaxations. Also, stars are opaque and surrounded by a lot of gas that doesn't emit light. All the light emission of a star happens within a shell of gas that only absorbs light and doesn't directly emit it. In contrast those nebulae hot enough to be ionized produce light all the edge and they tend to be very dispersed. The dispersion means the atoms are more likely to ionize than emit black body radiation. It is also important to remember that inside say the sun were the light is produced the density is so high it is pretty much like a solid and as such the energy levels tend to be more continuous than the discrete energy levels we see in the rarefied nebulae.
Thank you, this is what I was looking for.
Lasand
1st July 2011 - 10:56 PM
sithdarth has pretty well answered FBM's question.
Another take on the matter is that transitions of bound electrons involving the principle quantum numbers result in nice discrete lines.
In and around the sun, bound electrons can be energized to the continuous emission band extending from the limit of the discrete energy levels to the continuous region of possible energy values.
PhysOrg scientific forums are totally dedicated to science, physics, and technology. Besides topical forums such as nanotechnology, quantum physics, silicon and III-V technology, applied physics, materials, space and others, you can also join our news and publications discussions. We also provide an off-topic forum category. If you need specific help on a scientific problem or have a question related to physics or technology, visit the PhysOrg Forums. Here you’ll find experts from various fields online every day.
To quit out of "lo-fi" mode and return to the regular forums, please click
here.