DeepThought realized he left out one of the formulas in this set of equations. There was a sudden jump that had not be explained just after X was derived.
He sent me this corrected version...
QUOTE
Derived Conversion Values
Positive Charge
Meter = 3.3356409519815204957557671447492e-9 e/s
Kilogram = 3.501230577946767697834598968812e+54 e/s
Second = 1 e/s
Coulomb = 6,241,509,752,302,814,385.3767518217063 e/s
Joule = 3.8956443988091139382841461930519e+37 e/s
Ampere = 6.24150965×10^18 e/s
C (velocity of light) = 1 e/s
Negative Charge
meter = 3.3356409519815204957557671447492e-9 -e/s
kilogram = 3.501230577946767697834598968812e+54 -e/s
second = 1 -e/s
coulomb = 6,241,509,752,302,814,385.3767518217063 -e/s
joule = 3.8956443988091139382841461930519e+37 -e/s
ampere = 6.24150965×10^18 -e/s
C (velocity of light) = 1 -e/s
Notes: These values, whilst in the same units, do not have a one-to-one relationship.
Mass-Current-Space Equivalence Equation
Distance (e/s) ^ 2 = Mass (e/s) x (Current (e/s) ^2)
Electron
3,189,404,999,071,770,855,639,453.98532 e/s * 1 -e/s = 3,189,404,999,071,770,855,639,453.98532 -e/s
Notes: This formula is partially incorrect, the output must be tranformed to the meter through a different mechanism. This formula above is:
Mass (e/s) = Mass (e/s) x (Current (e/s) ^2).
In the end, it is "still distance", but in the transform of Mass. So, perhaps we should add something to denote this:
Distance_T_Mass (e/s) = Mass (e/s) x (Current (e/s) ^2)
Conversion To "Something Unknown"
Distance_T_Mass (e/s) / Joule (e/s) = ??? (No idea yet!)
3,189,404,999,071,770,855,639,453.98532 -e/s / 3.8956443988091139382841461930519e+37 e/s = 8.1871050654591619976025324000001e-14 -e/s
Notes: This is"something unknown" in the transform of Mass. So, we should define it as:
Distance_T_Mass (e/s) / Joule (e/s) = ???_T_Mass (e/s)
Now we have a choice of conversion methods, Contemporary Math or Tao Math. Choose one.
Conversion to the Kilogram (Contemporary Math)
joule (e/s) * "something unknown" (e/s) = Mass (e/s)
same as: joule (e/s) * ???_T_Mass (e/s) = Mass (e/s)
3.8956443988091139382841461930519e+37 e/s * 8.1871050654591619976025324000001e-14 -e/s
= 3,189,404,999,071,770,855,639,453.98532 -e/s
Note: This step should be very obvious, we are just reversing the previous step. It may seem stupid, but the value is used in the Tao math equation. We could just use the value of the Mass from the first equation.
To convert the Mass from e/s to Kg:
Mass (e/s) / Kilogram (e/s)
3,189,404,999,071,770,855,639,453.98532 -e/s / 3.501230577946767697834598968812e+54 e/s
= 9.1093829100000000000000000000001e-31 Kg
Conversion to the Kilogram (Using Tao Math)
Calculate Ratio
Joules:kilogram
3.501230577946767697834598968812e+54 e/s / 3.8956443988091139382841461930519e+37 e/s
= 89,875,517,873,681,764 e/s
Multiply "something unknown" (???_T_Mass (e/s)) by Joules to kilogram ratio (referred to "msubjtkr" in the below formulas)
8.1871050654591619976025324000001e-14 -e/s * 89,875,517,873,681,764 e/s
= 7,358.203076443854225649764839864 -e/s
Derive Unknown Value X
This is the formula that we need to solve:
???_T_Mass (e/s) ((Joule (e/s) / kilogram (e/s)) + x) = Mass (e/s) - msubjtkr (e/s)
This is a worked example (note how we just drop -msubjtkr (e/s) without balancing the equation)
8.1871050654591619976025324000001e-14 ((3.501230577946767697834598968812e+54 / 3.8956443988091139382841461930519e+37) + X) = 3,189,404,999,071,770,855,639,453.98532 -e/s
8.1871050654591619976025324000001e-14 (89,875,517,873,681,764 + X) = 3,189,404,999,071,770,855,639,453.98532
3,189,404,999,071,770,855,639,453.98532 / 8.1871050654591619976025324000001e-14 ?=( 89,875,517,873,681,764 + X
This new operator =( is Tao-Inverse-Equality. It means to invert the values to the right. (A type of "Not gate" - I'll explain later in another post.)
3.8956443988091139382841461930519e+37 = 89,875,517,873,681,764 + X
3.8956443988091139382841461930519e+37 - 89,875,517,873,681,764 = X
X = 3.8956443988091139382751586412645e+37 -e/s
3.8956443988091139382751586412645e+37 -e/s * 8.1871050654591619976025324000001e-14 = 3,189,404,999,071,770,855,632,095.7822435
Now we test the values we just derived:
3,189,404,999,071,770,855,632,095.7822435 + 7,358.203076443854225649764839864 = 3,189,404,999,071,770,855,639,453.98532
Finally, we convert the Mass from e/s to Kg:
Mass (e/s) / Kilogram (e/s)
3,189,404,999,071,770,855,639,453.98532 -e/s / 3.501230577946767697834598968812e+54 e/s
= 9.1093829100000000000000000000001e-31 Kg
Guys, I will have a look at your comments and get back to you on them. Something interesting has happened, it looks like the University of Melbourne have suggested something DeepThought was working on in 2010 may be accurate. That is, the big bang is a thermodynamic loss or freezing.