One spherical ball flying along x axis and another spherical ball flying 0.3 meters upper in oposit direction. Then they bounce to each over and need find with at what speed they will fly after bouncement and that will be they angles with x axis. Two balls are equal size and have radius r=0.5 meter. First ball flying at speed v_1=4 m/s and secon ball flying at speed v_2=7 m/s. So initialy two balls flying direction with x axis makes 0 degrees angles. Both balls mass is m=1000 kg. Balls flying in vacum.

Hi David,
Try using conservation of momentum.
You shouldn't even have any difficult vectors to deal with.
Peace,
Ron

I read that this excercise is astronomicaly hard. Is it true?

Hi David,
You can handle it. Take down the ball to 2 pt masses where they hit but use the radius (and separation) for your angles. Conservation of momentum (Pt) = Pi - Pf.
MV1(no angle needed) + MV2(no angle needed) = MV1(cos theta) + MV2(cos theta2)
If all serves me, I think you should be able to take it from there?
Peace,
Ron

Sry D,
You do need the angles before impact, but they should be congruent.

What is Pt, Pi, Pf, MV1 ? I need more formulas.

Check here

F1-F2 == Pi-Pf as far as can see.

And here2
If you like headaches :)

So p_1=m*v_1=4 (m/s)*1000 (kg)=4000.
p_2=7*1000=7000.
F=F2-F1=7000-4000=3000. But they bolunce to each over at angles so momentum must be not the same as they bounce directly in centers and if they bounce with edges. Or maybe momentum is the same, but still is diferent... I and don't get how momentum can help here...

How need find angles, anyway?
4000+7000=MV1(cos theta?) + MV2(cos theta2?)

Hint
3^2 + 4^2 = 5^2
are you looking at a right-angled triangle here?

Just give me solution, I don't see how to made it with vectors or triangles or whatever.

Thanks for jumping in C2, Yor_on,
I've been out.
Relax David. You've got to be able to work alot of this out yourself.
Draw a diagram of the balls hitting (on graph paper if you want), then draw lines from the center of the balls to where they touch. Like C2 said, you'll have a right triangle. Work out the masses X velocities (which will be a vector quantity of the original V x Cos of the angle off the X axis). The momentum going in should equal the momentum going out (P= momentum=MV). Let me know how you do.
Peace,
Ron

Too hard. I bet that Alphanumeric can't solve this.

Witty reply, but are you trying reverse psychology?
You can do this. What level are you in? This does not need calculus, but only trig. That tells me high school? AN can do (and even talk about things) that I cannot even fathom.
Have you tried or do you need more specific instructions? I will help you do this but I've passed my fair share of harder courses, now you have to put in your time!
Ask specifically where you are having prob's and I'll get you through If you want, though.
Peace,
Ron

How to made triangle? Then they bounce and at touching time, distance between them centers is 0.5+0.5=1. How farther finish triangle? Maybe one first ball radius along x axis is another brunch of triangle?
Anyway if for this excercise need very much calculus, then nevermain... If you can't solve it...

Hi David,
You shouldn't need calculus. I've been shooting from the hip so far to guide you along, but I'll crunch the numbers and be able to walk you right through it all as soon as I get a chance. Keep posted.
Peace,
Ron