Here's the question:

Imagine that you are a gymnast on a high bar, 90 degrees from vertical in a fully extended position (NO angular velocity at this point). Assuming that the center of mass of your body is 1.3m from your extended hands, and that your radius of gyration is 1.4m from your extended hands.. Calculate the torque created about the bar beginning at the start and for every 30 degrees until the rotation stops or changes direction. Assume that the friction from the bar in your hands produces a constant torque value of 30Nm.
My mass = 91.6kg or 898.6N

Okay, so.. I know that T = Fxd, but I don't know which force or distance to use.
Do I use F=898.6N, which is my weight? And do I use my center of mass as the distance or radius of gyration?
And how do I calculate my torque at 90 degrees from vertical, 60, 30, and 0 degrees?
I also don't understand where the friction of 30Nm comes into play..

There's another part to this question, which is: "Calculate angular velocity at each position assuming that the torque from the previous position was applied for a period of .1s"
but I'm more worried about finding out all the different torques..