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yor_on
Theorem : 3=4
Proof:
Suppose:
a + b = c
This can also be written as:
4a - 3a + 4b - 3b = 4c - 3c
After reorganizing:
4a + 4b - 4c = 3a + 3b - 3c
Take the constants out of the brackets:
4 * (a+b-c) = 3 * (a+b-c)
Remove the same term left and right:
4 = 3

Theorem : All numbers are equal to zero.
Proof: Suppose that a=b. Then
a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
a = 0

Theorem: 1$(dollar) = 1c(cent).
Proof:
And another that gives you a sense of
money disappearing...
1$ = 100c
= (10c)^2
= (0.1$)^2
= 0.01$
= 1c

Theorem: 1 = -1 .
Proof:
1/-1 = -1/1
sqrt[ 1/-1 ] = sqrt[ -1/1 ]
sqrt[1]*sqrt[1] = sqrt[-1]*sqrt[-1]
ie 1 = -1

Theorem: 4 = 5
Proof:
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5
Corvidae
It would be, except you can't divide by zero.
Gehn
QUOTE (Corvidae+Feb 22 2008, 07:37 PM)
It would be, except you can't divide by zero.

Which is how some people got to the 1 = 2 conclusion. Same method, different answer.

- Gehn biggrin.gif
yor_on
I find it evolutionary.
This is a field day for science.

I can see why some of you might doubt, but the truth is out there.

If one in a most serious manner can (and will) discuss larger and smaller infinity's and use the concept mathematically, then, why not by all means also divide by zero?
Edward 3
Only one small problem - you made the assumption that 3 = 4 and then used this assumption as the basis for your proof. But, no worse than a lot of the stuff we get on this forum.
yor_on
Edward? How do you see this???
There is as you say an assumption
Then comes a proof.

Clarify your point here.
Edward 3
Hi yor-on,
Read your "proof" in reverse !!!
regards
edward
yor_on
Aaah I see, you are serious :)
paul h
>Theorem: 1$(dollar) = 1c(cent).


You don't need the math to figure this one out,,, just go to the store and see what you get for the $
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